Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:
Step-by-step explanation:
- (3/4)
we know that
The measurement of the exterior angle is the semi-difference of the arcs which comprises
In this problem
∠FGH is the exterior angle
∠FGH=
∠FGH=
-----> equation A
--------> equation B
Substitute equation B in equation A
![100\°=(arc\ FEH-[360\°-arc\ FEH])](https://tex.z-dn.net/?f=100%5C%C2%B0%3D%28arc%5C%20FEH-%5B360%5C%C2%B0-arc%5C%20FEH%5D%29)
therefore
<u>The answer is</u>
The measure of arc FEH is equal to 
Answer:
Step-by-step explanation:
Givens
d1 = d
d2 = 75 - d
r1 = x
r2 = x + 7
t = 3
Equation
x*t + (x + 7)*t = 75
This equation represents the total distance travelled. Neither one of the cyclists have gone 75 miles, but they both have gone distances that equal a total of 75 miles.
Solution
3x + (x + 7)*3 = 75
3x + 3x + 21 = 75
6x + 21 = 75
6x = 54
6x/6 = 54/6
x = 9
Answer
The first cyclist is going 9 miles / hr
The second cyclist is going 16 miles / hour
(x + 2) = 3
-2 -2
0 1
x = 1
