Answer:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
x
=
0
y
=
0
+
5
y
=
5
Or
(
0
,
5
)
For:
x
=
−
2
y
=
−
2
+
5
y
=
3
Or
(
−
2
,
3
)
We can now plot the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-5)^2-0.125)((x+2)^2+(y-3)^2-0.125)(y-x-5)=0 [-20, 20, -10, 10]}
Now, we can shade the left side of the line.
graph{(y-x-5) >= 0 [-20, 20, -10, 10]}
Ten times ten (10 x 10) is equal to 100
Answer:
1/2
Step-by-step explanation:
I think so im not sure tho so sorry if its incorrect
Answer:
a =b = ![\frac{5\sqrt{5} }{5}](https://tex.z-dn.net/?f=%5Cfrac%7B5%5Csqrt%7B5%7D%20%7D%7B5%7D)
Step-by-step explanation:
![a^{2} +b^{2} = 5 ^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2Bb%5E%7B2%7D%20%3D%205%20%5E%7B2%7D)
a = b
![2a^{2} = 5 ^{2}](https://tex.z-dn.net/?f=2a%5E%7B2%7D%20%20%20%3D%205%20%5E%7B2%7D)
![2a^{2} = 25\\](https://tex.z-dn.net/?f=2a%5E%7B2%7D%20%20%20%3D%2025%5C%5C)
![a^{2} = \frac{25}{5}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%20%20%3D%20%5Cfrac%7B25%7D%7B5%7D)
a = ![\frac{5}{\sqrt{5} }](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B%5Csqrt%7B5%7D%20%7D)
must rationalize...
a =b = ![\frac{5\sqrt{5} }{5}](https://tex.z-dn.net/?f=%5Cfrac%7B5%5Csqrt%7B5%7D%20%7D%7B5%7D)
Answer:
x-int: x = -7 and y-int: y = 9
Step-by-step explanation:
9x - 7y = -63
x-int: 9x - 0 = -63
x = -7
y-int: -7y = -63
y = 9