Answer: What do you need, what grade are you in?
Step-by-step explanation:
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
Let w represent the width, hence:
length = w + 33, height = w - 13
Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w
V(w) = w³ + 20w² - 429w
Rate of change = dV/dw = 3w² + 40w - 429
When w = 38, dV/dw = 3(38)² + 40(38) - 429 = 5423
When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118
Rate = 10118 - 5423 = 4695 in³/in
The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in
Find out more on equation at: brainly.com/question/2972832
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Answer:
F=25
Step-by-step explanation:
10x+15=30x-5
15=20x-5
20=20x
1=x
30(1)-5
30-5
25
Answer:
a(c-b) = d
Use the distributive property, which states: x(y-z) = xy - xz
a(c-b) = ac - ab
ac - ab = d
Add ab on both sides
ac = d + ab
Divide both sides by a to isolate c
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Answer:
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<em><u>HOPE </u></em><em><u>IT </u></em><em><u>HELPS</u></em><em><u> ❤️</u></em>
