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barxatty [35]
3 years ago
13

What is each expression written using each base only once? 8 ^ 8 x 8 ^ 4

Mathematics
1 answer:
lys-0071 [83]3 years ago
3 0
The answeer is B 8 ^ 32 My older sis helped me on this one 
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Factorize this expression completely <br>using (a-b)² formula<br>3a²- 36a + 108​
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Answer:

3a^2 - 36a + 108  = (\sqrt{3}a - 6\sqrt{3} )^2

Step-by-step explanation:

3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2

so, a = \sqrt{3}  a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}

Therefore ,

3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2  = (\sqrt{3}a - 6\sqrt{3} )^2

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3 years ago
Solve for x: ( sqrt 7) ^ 6x = 49 ^ (x-6)
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Simplify each expression:<br> ( 5a^2b^3)(4ab^5)
DIA [1.3K]

Answer:

(22•5a3b4)

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

4ab • (5a2 • b3)

STEP

2

:

Multiplying exponential expressions :

2.1 a1 multiplied by a2 = a(1 + 2) = a3

Multiplying exponential expressions :

2.2 b1 multiplied by b3 = b(1 + 3) = b4

Final result :

(22•5a3b4)

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