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maw [93]
2 years ago
5

Write the equation of a line in slope-intercept form that has a slope of -8 and a y-intercept of (0,3).

Mathematics
1 answer:
Pavel [41]2 years ago
8 0
Y=ax+b
3=-8(0)+b
3=0+b
3=b

Y=-8x+3

(I think this is right, but u might want to double check)
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garik1379 [7]
The answer is 12x3y5 divided by 8x15x5y2
6 0
3 years ago
What is the common ratio for the geometric sequence?
Bezzdna [24]

Answer:

3 is the correct answer

u can find common ratio by dividing a specific term in GP by its preceding term. ...just as here

4/(4/3) = 3

also 12/4 = 3

also 36 /12 = 3

hence the common ratio for this GP is 3

hope it helped

Step-by-step explanation:

6 0
2 years ago
1. Which of the following is the standard form of y = (x – 3)(x – 7)?
Andrej [43]

9514 1404 393

Answer:

  b.  y = (x - 5)² - 4

Step-by-step explanation:

Here, we take "standard form" to mean "vertex form."

In the US, "standard form" would be ...

  y = x² -10x +21

Vertex form is ...

  y = (x -5)² -4 . . . . matches B

4 0
2 years ago
2. 2x+6y=6<br> -x-3y = -3<br> Solution(s):<br> PLEASE HELP SOLVE FOR X AND Y
allochka39001 [22]

Answer:

x = 0, y = 1

Step-by-step explanation:

2x + 6y = 6 → (1)

x - 3y = - 3 ( add 3y to both sides )

x = 3y - 3 → (2)

substitute x = 3y - 3 into (1)

2(3y - 3) + 6y = 6 ← distribute parenthesis and simplify left side

6y - 6 + 6y = 6

12y - 6 = 6 ( add 6 to both sides )

12y = 12 ( divide both sides by 12 )

y = 1

substitute y = 1 into (2)

x = 3(1) - 3 = 3 - 3 = 0

solution is x = 0 , y = 1

3 0
1 year ago
Find the fifth roots of 243(cos 260° + i sin 260°).
Dmitry [639]

Answer:

z1=3 cos (52 + i sin 52)

z2 =3 cos (124 + i sin 124)

z3 = 3 cos (196 + i sin 196)

z4 =3 cos (268 + i sin 268)

z5= 3 cos (340 + i sin 340)

Step-by-step explanation:

To find the fifth roots of 243 (cos 260° + i sin 260°).

z ^ 1/5 = r^1/5 ( cis ( theta + 360 *k)/5)  where k=0,1,2,3,4


So the first root of 243 (cos 260° + i sin 260°)  

is z1 =  243^1/5 ( cis ( 260 + 360 *0)/5)  

          3 cis ( 260/5)

        = 3 cis (52)

        = 3 cos (52 + i sin 52)


The second root of  243 (cos 260° + i sin 260°)  

is z2 =  243^1/5 ( cis ( 260 + 360 *1)/5)  

          3 cis ( 620/5)

        = 3 cis (124)

        = 3 cos (124 + i sin 124)


The third root of  243 (cos 260° + i sin 260°)  

is z3 =  243^1/5 ( cis ( 260 + 360 *2)/5)  

          3 cis ( 980/5)

        = 3 cis (196)

        = 3 cos (196 + i sin 196)


The fourth root of  243 (cos 260° + i sin 260°)  

is z4 =  243^1/5 ( cis ( 260 + 360 *3)/5)  

          3 cis ( 1340/5)

        = 3 cis (268)

        = 3 cos (268 + i sin 268)


The fifth root of  243 (cos 260° + i sin 260°)  

is z5 =  243^1/5 ( cis ( 260 + 360 *4)/5)  

          3 cis ( 1700/5)

        = 3 cis (340)

        = 3 cos (340 + i sin 340)

6 0
3 years ago
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