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Alex787 [66]
3 years ago
7

How many pairs of parallel sides does the traprzoid have

Mathematics
1 answer:
Tomtit [17]3 years ago
3 0

One pair Because the sides are the same side as each other top and bottom are not equal :)

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I have 30 coins consisting of nickels, and quarters. The total value of the coins is $4.10. How many of each kind do I have?
Vedmedyk [2.9K]
A=#nickels, b=#quarters

5a + 25b = 410 total value

5(a + 5b) = 410

a + 5b = 82

a + b = 30 total no. of coins

subtracting . . . 4b = 52

thus b = 13 and a = 17

13 quarters and 17 nickels = 13*25 + 17*5 = 410 = $4.10
5 0
4 years ago
The measure of the angles of a triangle are in the extended ratio of 3 : 7 : 10. Find the measures of the angles.
olga2289 [7]

Answer:

A. 27 degrees, 63 degrees, 90 degrees.

Step-by-step explanation:

Let the angle of the triangle be x

<u>Given the following data;</u>

3 : 7 : 10 = 3x : 7x : 10x

We know that the sum of the sides of a triangle is equal to 180 degrees.

3x + 7x + 10x = 180

20x = 180

x = 180/20

x = 9

<u><em>For the first side;</em></u>

3x = 3 × 9 = 27°

<em><u>For the second side;</u></em>

7x = 7 × 9 = 63°

<em><u>For the third side;</u></em>

10x = 10 × 9 = 90°

Therefore, the ratio of the angles of the triangle is 27° : 63° : 90°.

7 0
3 years ago
Read 2 more answers
The nearest ten 1202(38)
Misha Larkins [42]
The answer is 120240
4 0
3 years ago
kallie has a pottery business to make a certain piece she spends 3.68 on materials and 6.52 on labor. she then sells the pottery
Mrac [35]

Answer:

3/5 + 7/10 =  6/10 + 7/10 = 13/10 = 1 and 3/10 lbs. needed

She has 4/5 *3/1 bags = 12/5 = 2 and 2/5  pounds

2 2/5 - 1 3/10  = 2  4/10 - 1 3/10 = 1 and 1/10 pounds  left over

7 0
4 years ago
1. What is the minimum number of vertices in a binary tree with height 5? What is the maximum number of vertices in a binary tre
Hunter-Best [27]

Answer:

Height = 5

Minimum number of vertices in a binary tree

whose height is h.

So, there must be  At least one node at each of first h levels.

Minimum number of vertices = h

So, Minimum number of vertices of height 5 is 5

The maximum number of nodes in a binary tree of height h = 2^{h+1}- 1

Substitute h = 5

The maximum number of nodes in a binary tree of height 5 = 2^{5+1}- 1

The maximum number of nodes in a binary tree of height 5 = 63

So, the maximum number of vertices in a binary tree with height 5 is 63

6 0
3 years ago
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