Answer:
If the triangle is similar by any axiom then the ratio of their sides will be equal then you can easily find the side of the triangle
OR
You can also find it by congurency.
Hope this helps
Simplify the following:
x/((x - 2) (x + 9) (3 x - 6))
Factor 3 out of 3 x - 6:
x/(3 (x - 2) (x - 2) (x + 9))
Combine powers. x/((x - 2) (x + 9)×3 (x - 2)) = (x (x - 2)^(-1 - 1))/((x + 9)×3):
(x (x - 2)^(-1 - 1))/(3 (x + 9))
-1 - 1 = -2:
Answer: (x (x - 2)^(-2))/(3 (x + 9))
A) This one has no solutions because the answer of the equation is 0=-1 which isn't true.
b) 6t-3=3t+6 ==> 3t=9 ==> t=3 This means that this has one solution.
c) 6 (2m-3)-3m=2m-18+m ==> 12m-18=2m-18+m ==> 9m=0 ==> m=0 so this one has no solutions.
d) 10+3y-2=4y-y+8 ==> 8+3y=3y+8 ==> 0=0 ==> Infinitely many solutions.
~Hope I helped!~
That method of representing the number would produce ...
2.750389 x 10⁶ .
Answer:
r = p(-b/a)
Step-by-step explanation:
Let p(x) = q(x)(ax + b) + r(x) where q(x) is the quotient when p(x) is divided by ax + b and r(x) is the remainder.
Since ax + b is a first degree polynomial, r(x) is one power less than ax + b is is just a constant, r.
So, p(x) = q(x)(ax + b) + r
Now, p(x) = r when q(x)(ax + b) = 0
since q(x) ≠ 0, ax + b = 0 ⇒ ax = -b ⇒ x = -b/a
⇒ p(x) = r when x = -b/a
So, r = p(-b/a)
So, the remainder when a polynomial function p(x) is divided by a first degree polynomial ax + b is p(-b/a)
