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ololo11 [35]
2 years ago
9

Please help click on the image below

Mathematics
2 answers:
Kay [80]2 years ago
6 0
The answer is 70, because if subtract 85-3 for 3 days it will equal 70, btw if its wrong SORRY.
Stolb23 [73]2 years ago
4 0
The answer is 70 because if you multiply the money she spends by the number of days you get 15. Then subtract 15 from 85 and you will get 70
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Rob colored 1/4 of a rectangle. what is another way to name 1/4?
Morgarella [4.7K]
One-Fourth is another way 


3 0
3 years ago
Read 2 more answers
The exact value of cos 13pi/8 is
Naily [24]

Answer:

answer is : Cos(13pi/8) = 0.3826  

Step-by-step explanation:

We have, Cos (13pi/8)

Since 13pi/8 can be shown as 3pi/2 < 13pi/8 < 2pi

Hence 13pi/8 lies on fourth quadrant.

In fourth quadrant cosine will be positive.

Cos (13pi/8) = cos(3pi/2 + pi/8)

applying formula cos(A+B) = cos A cosB - sinAsinB

i.e Cos(3pi/2 + pi/8) = cos(3pi/2)cos(pi/8) - sin(3pi/2)sin(pi/8)

∵ Remember cos(3pi/2) =0 , sin(3pi/2) = -1

     Cos(3pi/2 + pi/8) = 0 cos(pi/8) - (-1)sin(pi/8)

     Cos(3pi/2 + pi/8) = 0  + 0.3826

      Cos(3pi/2 + pi/8) = 0.3826

Hence we got Cos(13pi/8) = 0.3826                          

6 0
3 years ago
Read 2 more answers
Let A, B, C and D be sets. Prove that A \ B and C \ D are disjoint if and only if A ∩ C ⊆ B ∪ D
ANEK [815]

Step-by-step explanation:

We have to prove both implications of the affirmation.

1) Let's assume that A \ B and C \ D are disjoint, we have to prove that A ∩ C ⊆ B ∪ D.

We'll prove it by reducing to absurd.

Let's suppose that A ∩ C ⊄ B ∪ D. That means that there is an element x that belongs to A ∩ C but not to B ∪ D.

As x belongs to A ∩ C, x ∈ A and x ∈ C.

As x doesn't belong to B ∪ D, x ∉ B and x ∉ D.

With this, we can say that x ∈ A \ B and x ∈ C \ D.

Therefore, x ∈ (A \ B) ∩ (C \ D), absurd!

It's absurd because we were assuming that A \ B and C \ D were disjoint, therefore their intersection must be empty.

The absurd came from assuming that A ∩ C ⊄ B ∪ D.

That proves that A ∩ C ⊆ B ∪ D.

2) Let's assume that A ∩ C ⊆ B ∪ D, we have to prove that A \ B and C \ D are disjoint (i.e.  A \ B ∩ C \ D is empty)

We'll prove it again by reducing to absurd.

Let's suppose that  A \ B ∩ C \ D is not empty. That means there is an element x that belongs to  A \ B ∩ C \ D. Therefore, x ∈ A \ B and x ∈ C \ D.

As x ∈ A \ B, x belongs to A but x doesn't belong to B.  

As x ∈ C \ D, x belongs to C but x doesn't belong to D.

With this, we can say that x ∈ A ∩ C and x ∉ B ∪ D.

So, there is an element that belongs to A ∩ C but not to B∪D, absurd!

It's absurd because we were assuming that A ∩ C ⊆ B ∪ D, therefore every element of A ∩ C must belong to B ∪ D.

The absurd came from assuming that A \ B ∩ C \ D is not empty.

That proves that A \ B ∩ C \ D is empty, i.e. A \ B and C \ D are disjoint.

7 0
3 years ago
Leonardo is running the 100 meter dash at his school’s track meet. After 78 meters, his right shoe falls off! He can’t stop to p
AveGali [126]

100 meters -78 meters =21 m


6 0
2 years ago
Read 2 more answers
Bengus the expert blacksmith forged 32 swords from copper, twice as many swords from iron, and 19 swords from mythril. Estimate
Anna35 [415]

Answer: 115 swords

Step-by-step explanation:

He forged 32 swords from copper, 2*32 from iron and 19 from mythril.  Thus, he forged 32+(32*2)+19, or 32+64+19, or 115 swords.

<em>Hope it helps <3</em>

8 0
3 years ago
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