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ziro4ka [17]
3 years ago
10

8.6 dived by 3.3 and the other way around

Mathematics
1 answer:
german3 years ago
6 0
8.6 divided by 3.3 = 2.60606
3.3 divided by 8.6 = 0.383721
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PLEASE EXPLAIN TOO SO I CAN SOLVE OTHER SIMILAR ONES.
jeka57 [31]

Answer: x = 30' , y = 45'

hope this helps

Step-by-step explanation:

U is 90' it's a right triangle

well simple VRT you already know 2 angles which is 60' and 90'

R = 60'

V = 90'

T = x

you know that a triangle = 180'

so you do

180 - 60 - 90 = x

30 = x

if you want to do y

then you already know that U is 90' on both sides.

since you also know S,

S = 45'

U = 90'

V = y

180 - 90 - 45 = y

45 = y

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2 years ago
Without drawing the graphs, find the points of intersection of the lines:
tankabanditka [31]
The answer is (4,7) :)
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3 years ago
Find the product. write your answer in exponential form 9²•9-⁶​
enyata [817]

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3 0
2 years ago
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A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.
irakobra [83]

Answer:

The integral is equal to 5\sec^2(2x)+C for an arbitrary constant C.

Step-by-step explanation:

a) If u=\tan(2x) then du=2\sec^2(2x)dx so the integral becomes \int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C. (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case u=\sec(2x) hence du=2\tan(2x)\sec(2x)dx. We rewrite the integral as \int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C.

c) We use the trigonometric identity \tan(2x)^2+1=\sec(2x)^2 is part b). The value of the integral is 5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C. which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.  

3 0
3 years ago
PLZ NO FILES I really need help
Lelechka [254]
53 is the answer


Explanation

Yes
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3 years ago
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