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AnnZ [28]
3 years ago
11

Find the sum of the infinite geometric series, if it exists.

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

So the series looks something like this:

\Sigma_{n=4}^{\infty}\frac{n-1}{16} \\\frac{1}{16}\Sigma_{n=4}^{\infty}n-1

If \lim_{n\rightarrow\infty}\neq than \Sigma{a_n} diverges. So we must apply limit infinity property:

\lim_{n\rightarrow\infty}(ax^n+\dots+bx+c)=\infty, a>0 and n is odd.

So...

\lim_{n\rightarrow\infty}n-1=\infty

The series diverges.

Hope this helps.

r3t40

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Step-by-step explanation:

Lets first find the remainder when p(x) is divided by x-2

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