Lets note the change between each of the numbers in the sequence:
-2 --> 6 ---> 14
Next, make an equation between each of these numbers with x being the change between them
-2+ x = 6, 6 + x = 14 .
Now, solve each of these equations:
-2+ x = 6 --> -2+ x = 6 <em>Add 2 on both sides to cancel out the -2 </em>--> <em>x = 8</em>
6+ x = 14 --> -2+ x = 6 Minus <em>6 on both sides to cancel out the 6 </em>--> <em>x = 8</em>
<u><em>From this, the common difference will be 8.</em></u>
Hope that helps.
Answer:
The ages of the children are 6, 9 and 12.
Explanation:
Let x= the age of the youngest child.
If the oldest child is twice the age of the youngest, the age of the oldest child is twice x or 2x.
If the middle child is 3 years older than the youngest, the age of the middle child is x+3.
If the sum of their ages is 27, then
x+2x+x+3=27aaa(Combine like terms)
4x+3=27aaa
aa−3a−3aaa(Subtract 3 from both sides)
4x=24
4x4=24aaa(Divide both sides by 4)
Answer:
PR = 10
Step-by-step explanation:
PR = 
The coordinates for P and R are (0,4) and (-6,-4) respectively.
So you plug in the values:
PR = 
PR = 
PR = 
PR = 
PR = 10
Answer:
3m +2≤ 53
Step-by-step explanation:
thats just how it goes logically
If the -8 is under the square root, then...
OR
If the -8 is not under the square root, then...
Either way, we replace x with -3 and simplify.
For more information, refer to the direct substitution rule for limits.
