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Angelina_Jolie [31]
3 years ago
15

Write 4 litres 150 ml to the nearest half a lirter

Mathematics
1 answer:
babymother [125]3 years ago
6 0
1 litre = 1000 ml

1 ml = 1 / 1000=  0.001 litre

150 ml = 150 / 1000 = 0 .15 litre

4 + 0.15 = 4.15 litres

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5 0
3 years ago
The length of a rectangular room is 6 feet longer than twice the width. If the room perimeter is 168 feet, what are the room's d
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hope u like the answer if yes mark !e brainlist
3 0
3 years ago
Read 2 more answers
Midpoint of the segment between the points (−5,13) and (6,4)
Leokris [45]

Answer: (0.5,8.5)

Step-by-step explanation:

We need to use the following formula to find the Midpoint "M":

M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Given the points (-5,13) and (6,4) can identify that:

x_1=-5\\x_2=6\\\\y_1=13\\y_2=4

The final step is to substitute values into the formula.

Therefore, the midpoint of the segment between the points (-5,13) and (6,4) is:

M=(\frac{-5+6}{2},\frac{13+4}{2})\\\\M=(\frac{1}{2},\frac{17}{2})\\\\M=(0.5,8.5)

6 0
3 years ago
Read 2 more answers
Guy ran at 13 km/hr. what was guys speed in MPH?
Assoli18 [71]

The guy ran at a speed of 8.07783 MPH

Here's how I got my answer:

1 km/hr. = 0.621371

So, if you do 0.621371 * 13 you will get your answer: 8.07783 MPH

7 0
3 years ago
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A bottling company uses a filling machine to fill plastic bottles with cola. The bottles are supposed to contain 300 milliliters
PilotLPTM [1.2K]

Answer:

e. 0.0072

Step-by-step explanation:

We are given that a bottling company uses a filling machine to fill plastic bottles with cola. And the contents vary according to a Normal distribution with Mean, μ = 298 ml and Standard deviation, σ = 3 ml .

 Let    Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)  where, Xbar = mean contents of six randomly

                                                                     selected bottles

                                                          n = sample size i.e. 6    

So, Probability that the mean contents of six randomly selected bottles is less than 295 ml is given by, P(Xbar < 295)

 P(Xbar < 295) = P( \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{295 - 298}{\frac{3}{\sqrt{6} } } ) = P(Z < -2.45) = P(Z > 2.45)

Now, using z% score table we find that P(Z > 2.45) = 0.00715 ≈ 0.0072 .

Therefore, option e is correct .

7 0
4 years ago
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