All categories

3 years ago

Given h (x) = -x-4,solve for x when h (x) =9

Mathematics

1 answer:

Leona [35]3 years ago

8 0

Answer:

–13

Step-by-step explanation:

h(x) = –x –4

h(x) = 9

–x –4 = 9

–x = 9 + 4

–x = 13

x = –13

<em><u>pick me as the brainliest. thx</u></em>

You might be interested in

Complete the statement with equal to, greater than, or less than.

enyata [817]

2 x 2/9 Will Be Less Than 2

5 0

2 years ago

6 points

kodGreya [7K]

Answer:

$y=-2\,(x+3)^2-3$

Step-by-step explanation:

Notice that they are asking you to write the equation of the parabola in vertex form, that is using the coordinates of the vertex $(x_v,y_v)$ in the expression:

$y-y_v=a\,(x-x_v)^2\\y=a\,(x-x_v)^2+y_v$

we can start by directly replacing the given vertex coordinates (-3, -3) in the expression, and then using the extra info on the point the parabola goes through in order to find the parameter $a$ :

$y=a\,(x-x_v)^2+y_v\\y=a\,(x+3)^2+(-3)\\y=a\,(x+3)^2-3\\-5=a\,(-2+3)^2-3\\-5=a\,(1)-3\\a=-5+3\\a=-2$

So, now we can write the full expression for the parabola:

$y=a\,(x+3)^2-3\\y=-2\,(x+3)^2-3$

8 0

3 years ago

A wheel assembly is

Basile [38]

Answer:

The total weight of the assembly is 7 pounds.

Step-by-step explanation:

The total weight of the assembry is found by the sum of the weights of each components.

We have:

2 wheels, each weighing 2.6 pounds, so 2*2.6 = 5.2 pounds

An axle, which weighs 1.8 pounds, so 5.2+1.8 = 7 pounds

The total weight of the assembly is 7 pounds.

5 0

3 years ago

Show that if S1 and S2 are subsets of a vector space V such that S1 c S2 then span(S1) c span(S2). In particular, if S1 c S2 the

klemol [59]

Answer:

See proof below

Step-by-step explanation:

Assume that V is a vector space over the field F (take F=R,C if you prefer).

Let $x\in span(S_1)$ . Then, we can write x as a linear combination of elements of s1, that is, there exist $v_1,v_2,\cdots,v_k \in S_1$ and $a_1,a_2,\cdots,a_k\in F$ such that $x=a_1v_1+a_2v_2+\cdots+a_kv_k$ . Now, $S_1\subseteq S_2$ then for all $y\in S_1$ we have that $y\in S_2$ . In particular, taking $y=v_j$ with $j=1,2,\cdots,k$ we have that $v_j\in S_2$ . Then, x is a linear combination of vectors in S2, therefore $x\in span(S_2)$ . We conclude that $span(S_1)\subseteq span(S_2)$ .

If, additionally $S_2\subseteq S_1$ then reversing the roles of S1 and S2 in the previous proof, $span(S_2)\subseteq span(S_1)$ . Then $span(S_1)\subseteq span(S_2)\subseteq span(S_1)$ , therefore $span(S_1)=span(S_2)$ .

5 0

3 years ago

You mix the letters m,a,t,h,e,m,a,t,i,c,a and l thoroughly without looking you draw one letter probability p(A) . write the prob

erastovalidia [21]

There are 12 total letters, of which 3 are A's.

This means you have a $\dfrac3{12}=\dfrac14=0.25=25\%$ probability of randomly selecting an A.

3 0

3 years ago