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Varvara68 [4.7K]
3 years ago
9

Given h (x) = -x-4,solve for x when h (x) =9

Mathematics
1 answer:
Leona [35]3 years ago
8 0

Answer:

–13

Step-by-step explanation:

<h2>—Math </h2>

h(x) = –x –4

h(x) = 9

–x –4 = 9

–x = 9 + 4

–x = 13

x = –13

<em><u>pick me as the brainliest. thx</u></em>

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D

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What is the value of 2x3 + x2 – x when x = 3?
Bad White [126]

Answer:

12

Step-by-step explanation:

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TL;DR

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7 0
3 years ago
The end points of a diameter of a circle are (6,2) and (-4,7).
motikmotik

Answer:

Step-by-step explanation:

The standard form equation of a circle with radius r is expressed as

( x − h )^2 + ( y − k )^2 =r ^2 ,

where r represents the radius

h and k are the coordinates of the center of the circle C( h , k )

To determine the coordinates at the center of the circle, the midpoint formula would be used. It is expressed as

[(x1 + x2)/2 , (y1 + y2)/2]

Midpoint of the circle =

(6 - 4)/2 , (2 + 7)/2 = (1, 4.5)

h coordinate of the center = 1

k coordinate of the center = 4.5

r^2 = (x - h)^2 + (2 - k)^2

r^2 = (6 - 1)^2 + (2 - 4.5)^2

r^2 = 5^2 + (- 2.5)^2 = 25 + 6.25

r^2 = 31.25

Substituting r^2 = 31.25, h = 1 and k = 4.5 into (x − h )^2 + ( y − k )^2 = r^2, the standard equation of the circle becomes

(x − 1 )^2 + ( y − 4.5 )^2 = 31.25

3 0
3 years ago
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