No. Both legs can be 10, but the hypotenuse has to equal
Y^4-4y^3+7y^2-6y-2y^3+8y^2-14y+12=
y^4-6y^3+15y^2-20y+12
or
y^3-4y^2+7y-6=y^3-4y^2+4y+3y-6=
y(y^2-4y+4)+3(y-2)=
y(y-2)^2+3(y-2)=(y-2)[y(y-2)+3]=(y-2)(y^2-2y+3)
(y^3-4y^2+7y-6)(y-2)=(y-2)^2(y^2-2y+3)
1/5 hour = 1 mile
Multiply each side by 5
1 hour = 5 miles.
Answer:
$50
Step-by-step explanation:
15x18=270
1170-270=900
900/18=50