When are two expression considered to be equivalent
1 answer:
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Find the perpendicular line then find the intersection then find the point
perpendicular lines have slopes that are perpendicular
the slopes multiply bo -1
y=mx+b
m=slope
y=2x-3
2 is slope
2 times what=-1
what=-1/2
the equation is
y-3=-1/2(x-8) or
y=(-1/2)x+7
find intersection
at (4,5)
distance bwetweeen (8,3) and (4,5)
D=
D=
D=
D=
D=2√5
distance= 2√5
perpendicular lines have slopes that are perpendicular
the slopes multiply bo -1
y=mx+b
m=slope
y=2x-3
2 is slope
2 times what=-1
what=-1/2
the equation is
y-3=-1/2(x-8) or
y=(-1/2)x+7
find intersection
at (4,5)
distance bwetweeen (8,3) and (4,5)
D=
D=
D=
D=
D=2√5
distance= 2√5
Answer:
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Step-by-step explanation:
Given
In 1990; Income= $39000
In 2010; Income= $70768
Solving (a): An equation in form of f(x) = ax + b
First, we need to determine the slope, a
Taking y as income and x as year index.
When x = 0; y = 39000
When x = 20; y = 70768
Substitute these values in the above formula
Next, is to determine the formula using:
<em>Considering :When x = 0; y = 39000, we have</em>
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<em>Make y the subject of formula</em>
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<em />
<em>Express y as a function of x</em>
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Solving (b): Income in 2005
<em>In 2005, x = 15</em>
So:
becomes