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2 years ago

Help me pls i dont get this

Mathematics

2 answers:

Gnoma [55]2 years ago

5 0

Answer: B. 80

Step-by-step explanation:

Solve the equation they've given you:

$\frac{3}{4} S=60\\\frac{3S}{4} =60\\3S=60*4\\3S=240\\S=80$

hoa [83]2 years ago

5 0

Answer:

B. 80

Step-by-step explanation:

(3/4)S = 60

You want to isolate S. S is being multiplied by 3/4.

You need to multiply 3/4 by its reciprocal to get rid of the 3/4 on the left side.

The reciprocal of 3/4 is 4/3.

The rule with equations is that you are allowed to multiplied both sides of an equation by the same number. Multiply both sides of the equation by 4/3.

4/3 * (3/4) * S = 4/3 * 60

12/12 * S = 4/3 * 60/1

1 * S = 240/3

S = 80

Answer: B. 80

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Answer: r - 5 = 8

Step-by-step explanation:

From the question, we are informed that Skye ran r laps today at soccer practice while Nadine ran five fewer laps than Skye.

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3 years ago

A certain positive integer has exactly 20 positive divisors. What is the smallest number of primes that could divide the integer

Alika [10]

As per my explanation to (b) above, the largest number of primes that could factor such a number is 4.

Note that 2,3,5 and 7 are the smallest primes, then use the reasoning from

(b) above. we are looking for four exponents, that, when 1 is added to each and all are multiplied together, would equal 20.

But no such integers k, l, m, and n exist such that (k + 1)(l + 1)(m + 1) (n + 1) = 20 where k, l,m, and n ≥ 1 so this number, whatever it is, can't have 4 prime factors

Let's drop 7 out of the mix and suppose it has just 3 prime factors 2, 3, and 5 again we are looking for three exponents, that, when 1 is added to each and all are multiplied together, would equal 20. Put another way, we are looking for k, l and m ≥ 1 such that (k + 1)(l + 1)(m + 1) = 20

Note that the only possibility here is when we have 2 *2 *5 = 20 and the smallest possible product would be 2^(4 )* 3^(1) * 5^(1) = 2^4 * 3 * 5 = 240

Now......the only remaining possibility is that this number is composed of the two smallest primes, 2 and 3, and we are looking for some k and l ≥ 1 such that (k + 1)(l + 1) = 20 clearly, the only possibilities are when k = 4 and l = 5, or vice-versa

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1 year ago

Manny makes dinner using 1 box of pasta and 1 jar of sauce. if pasta is sold in packages of 6 boxes and sauce is sold in package

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2 years ago

a manufacturer of cookies and crackers does a small survery of the age at sale of one of its brands. A tandom sample of 225 reta

Effectus [21]

Answer:

$t=\frac{56.7-60}{\frac{30}{\sqrt{225}}}=-1.65$

$df=n-1=225-1=224$

The p value would be:

$p_v =P(t_{(224)}$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we cna conclude that the true mean is less than 60 at 10% of significance.

Step-by-step explanation:

Information given

$\bar X=56.7$ represent the sample mean of interest

$s=20$ represent the sample standard deviation

$n=225$ sample size

$\mu_o =60$ represent the value to check

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test

System of hypothesis

we want to check if the true mean is lower than 60, so thn the system of hypothesis are:

Null hypothesis: $\mu \geq 60$

Alternative hypothesis: $\mu < 60$

The statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replcing into the formula we got:

$t=\frac{56.7-60}{\frac{30}{\sqrt{225}}}=-1.65$

P value

The degrees of freedom are given by:

$df=n-1=225-1=224$

The p value would be:

$p_v =P(t_{(224)}$

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is less than 60 at 10% of significance.

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