<span><span><span>2x</span>−1</span>≤<span>x5
</span></span>Let's find the critical points of the inequality.
<span><span><span>2x</span>−1</span>=<span>x^5
</span></span><span><span><span><span>2x</span>−1</span>−<span>x^5</span></span>=<span><span>x^5</span>−<span>x^5 </span></span></span>(Subtract x^5 from both sides)
<span><span><span><span>−<span>x^5</span></span>+<span>2x</span></span>−1</span>=0
</span><span><span><span>(<span><span>−x</span>+1</span>)</span><span>(<span><span><span><span><span>x^4</span>+<span>x^3</span></span>+<span>x^2</span></span>+x</span>−1</span>)</span></span>=0 </span>(Factor left side of equation)
<span><span><span><span>−x</span>+1</span>=<span><span><span><span><span><span>0<span> or </span></span><span>x^4</span></span>+<span>x^3</span></span>+<span>x^2</span></span>+x</span>−1</span></span>=0 </span>(Set factors equal to 0)
<span><span><span>x=<span><span>1<span> or </span></span>x</span></span>=<span><span>0.51879<span> or </span></span>x</span></span>=<span>−<span>1.290649</span></span></span>
Line 1 only should be the answer!
Answer: We can use tangent here to find the length of the flagpole
First, find the length of the building + the flag pole
tan 32 = x/300
x=300tan32=187.460805573
(length of building + flagpole)
find length of building
tan 30 = x/300
x=173.205080757
subtract
187.460805573-173.205080757=14.255724816
round, length of flagpole = 14 feet
Answer:
A ≈ 35.3 units²
Step-by-step explanation:
Calculate the radius CB using Pythagoras' identity in the right triangle.
CB² + AB² = AC²
CB² + 6² = 9²
CB² + 36 = 81 ( subtract 36 from both sides )
CB² = 45 = r²
Then area of quarter circle is
A = 
× πr² = × π × 45 ≈ 35.3
Answer:
b. 0.86, 0.87
Step-by-step explanation:
a. Find attached solution to a
