Question

A2+5a+6=0{a}^{2} + 5a + 6 = 0" alt=" {a}^{2} + 5a + 6 = 0" align="absmiddle" class="latex-formula">

Answer 1

You did a good job of sharing this quadratic equation in proper symbolic notation, but you haven't yet shared the instructions for this problem.

I will assume that you are to find the roots / zeros of a^2+5a+6=0. Factoring results in (a+3)(a+2)= 0, from which we deduce that a = -3 and a = -2.

The solution set is {-3, -2}.

Answer 2

we are given

$a^2+5a+6=0$

we can use factoring formula

$a^2-(m+n)a+mn=(a-m)(a-n)$

we can compare

and we get

$m+n=-5$

$mn=6$

now, we can solve for m and n

and we get

$m=-3 , n=-2$

now, we can use formula

and we get

$a^2+5a+6=(a+3)(a+2)$

now, we can set it equal to 0

$a^2+5a+6=(a+3)(a+2)=0$

$(a+3)=0$

$a=-3$

$a+2=0$

$a=-2$

so, we will get

$a=-2,a=-3$.............Answer