Answer:
(-12 , 2)
Step-by-step explanation:
<u>GIVEN :-</u>
- Co-ordinates of one endpoint = (-4 , -10)
- Co-ordinates of the midpoint = (-8 , -4)
<u>TO FIND :-</u>
- Co-ordinates of another endpoint.
<u>FACTS TO KNOW BEFORE SOLVING :-</u>
<em><u>Section Formula :-</u></em>
Let AB be a line segment where co-ordinates of A = (x¹ , y¹) and co-ordinates of B = (x² , y²). Let P be the midpoint of AB . So , by using section formula , the co-ordinates of P =
<u>PROCEDURE :-</u>
Let the co-ordinates of another endpoint be (x , y)
So ,
First , lets solve for x.
Now , lets solve for y.
∴ The co-ordinates of another endpoint = (-12 , 2)
Well, we need to consider the x and y coordinates of the giben points, and check wether the y coordinate is greater than twice the x coordinate minus 1 (i.e. 2x-1):
- For the first point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is 2, and 2>-1. So, this point is a solution.
- For the second point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 2, and 2<7. So, this point is not a solution.
- For the third point, the x coordinate is 0. So, 2x-1 = -1. The y coordinate is -10, and -10<-1. So, this point is not a solution.
- For the fourth point, the x coordinate is 4. So, 2x-1 = 7. The y coordinate is 1, and 1<7. So, this point is not a solution.
Let x be this number:
√x = 12
let's square both sides:
(√x)² = (12)²
x = 144
