Answer: The net ionic equation will be as follows.
![CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)](https://tex.z-dn.net/?f=CH_%7B3%7DCOO%5E%7B-%7D%28aq%29%20%2B%20H_%7B2%7DO%28l%29%20%5Crightleftharpoons%20CH_%7B3%7DCOOH%28aq%29%20%2B%20OH%5E%7B-%7D%28aq%29)
Explanation:
The chemical equation for the given reaction is as follows.
![CH_{3}COONa(aq) + H_{2}O(l) \rightleftarrow CH_{3}COOH(aq) + NaOH(aq)](https://tex.z-dn.net/?f=CH_%7B3%7DCOONa%28aq%29%20%2B%20H_%7B2%7DO%28l%29%20%5Crightleftarrow%20CH_%7B3%7DCOOH%28aq%29%20%2B%20NaOH%28aq%29)
We know that a strong acid or base will dissociate completely into a solvent whereas a weak acid or base dissociates partially into the solvent. Hence, the ionic equation will be as follows.
Now, we will cancel the spectator ions from the above equation. Therefore, the net ionic equation will be as follows.
![CH_{3}COO^{-}(aq) + H_{2}O(l) \rightleftharpoons CH_{3}COOH(aq) + OH^{-}(aq)](https://tex.z-dn.net/?f=CH_%7B3%7DCOO%5E%7B-%7D%28aq%29%20%2B%20H_%7B2%7DO%28l%29%20%5Crightleftharpoons%20CH_%7B3%7DCOOH%28aq%29%20%2B%20OH%5E%7B-%7D%28aq%29)
or,
I believe the answer to your question is none of the above
<span>47.88 g/mol is the awsner your welcome</span>
Answer:
CU
Explanation:
Cu is the correct answer if I'm correct
A, true is the answer and cluke u help me please