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ra1l [238]
2 years ago
9

In the triangle below, suppose that m/Q = (2x-3)°, m/R= (5x+7)°, and m/S=xº.

Mathematics
1 answer:
o-na [289]2 years ago
7 0

Answer:

Please Attach The Pic so someone can answer.....

Step-by-step explanation:

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What is the given point on the line of this equation y +2 = 5/3(x-3)
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6

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Solve x then y after..

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Elena has more roses than Lin. Lin has 8 roses and Elena has x roses. Which expression represents the number of roses Elena has?
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What would be the next number in the pattered 64, 16,4,1
alekssr [168]

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6 0
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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%20lnx%20%7D%20" id="TexFormula1" title=" \sqrt[4]{ lnx } " alt=" \sqrt[4]
Kamila [148]

Use the power rule for differentiation:

\dfrac{\text{d}}{\text{d}x} (f(x))^k = k(f(x))^{k-1}f'(x)

You can use this formula if you remember that a root is just a rational exponential:

\sqrt[4]\ln(x) = (\ln(x))^{\frac{1}{4}}

So, remembering that the derivative of the logarithm is 1/x, you have

\dfrac{\text{d}}{\text{d}x} (\ln(x))^{\frac{1}{4}} = \frac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x}

Which you can rewrite as

\dfrac{1}{4}(\ln(x))^{\frac{1}{4}-1}\dfrac{1}{x} =\dfrac{1}{4}(\ln(x))^{\frac{-3}{4}}\dfrac{1}{x} =\dfrac{1}{4}\dfrac{1}{\sqrt[4]{\ln(x))^3}}\dfrac{1}{x} = \dfrac{1}{4x\sqrt[4]{\ln(x))^3}}

3 0
3 years ago
Help me please , will mark brainliest
Gnom [1K]

Answer:

1. 160ft

2. 218.64ft

3. 84ft

4.  140.67

Step-by-step explanation:

L*W*H / 3

5 0
3 years ago
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