Answer:
5.1
Step-by-step explanation:
Before we calculate the y value for the point Q that is located two thirds the distance from point P to point R, we need to get the distance of point p from point R using the formula for calculatingf the distance between two points
D = √(x2-x1)²+(y2-y1)²
Given P(−2, 7), and R(1, 0)
RP = √(1-(-2))²+(0-7)²
RP = √3²+(-7)²
RP = √9+49
RP =√58
To get the y value for point Q that is located two thirds the distance from point P to point R, this will give
PQ = y = 2/3 of √58
= 5.1
x = 375 and y = 6300. Option C.
Step-by-step explanation:
From the given data we need to find the value of x and y.
First, we will find out the ratio of area and the force.
= 
So,
or, x = 
= 375
Again,
or, y = 420×15 = 6300
Hence,
x = 375 and y = 6300.
5x + 2y=50
or
5x + 2y<=50 (less than or equal to)
then
x + 2y=30
or
x + 2y<=30(less than or equal to)
Answer:
y = x + 3
Step-by-step explanation:
This is because the number is increasing by three each time and if you substituted the variable x with a number the answer is true.
1/2
When you put a square root into exponential form, the square root turns into an exponential fraction. Since the square root is 2, our fraction would be 1/2
If our root was a cube root, our exponent would be 1/3, etc.
