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Anastaziya [24]
3 years ago
7

1 3/4 +3/4 show ur work lol

Mathematics
2 answers:
butalik [34]3 years ago
8 0

Answer:

5/2

Step-by-step explanation:

1 3/4 = 4/4 + 3/4 = 7/4

7/4 + 3/4 = 10/4 =5/2

Eduardwww [97]3 years ago
7 0

Answer:

10/4

Step-by-step explanation:

3/4 + 3/4 is 6/4 plus 1 (4/4) is 10/4 or 5/2

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2= 7/9 x 6 + b solve for b
netineya [11]

Answer:

8/3

Step-by-step explanation:

7/9 x 6

14/3

14/3 - 2

8/3

5 0
3 years ago
Why is it important to know how to estimate quotients?
Zigmanuir [339]
In the real world you are not going to have a calculator on you 24/7. Nor will you have a pencil or paper to do longhand. You need to know how to accurately estimate your answers in order to be successful.
8 0
3 years ago
A market sells blueberries for $3 per pint. The first day, the market sold a total of $35 worth of blueberries. The second day,
Eddi Din [679]

Answer:Around 50 pints

Step-by-step explanation:

$35=$40

$47=$50

$57=$60

$40+$50+$60=$150/3=50

6 0
3 years ago
Brian flips a fair coin 3 times. What is the probability of getting exactly 2 tails?
sammy [17]

Answer:

3/8

Step-by-step explanation:

The possible outcomes

TTT TTH THT THH  HHH HHT HTH HTT  = 8 outcomes

There are TTH THT HTT  3 with exactly two tails

P ( exactly 2 tails) = 3/8

7 0
3 years ago
Read 2 more answers
A box contains 5 red balls, 6 white balls and 9 black balls. Two balls are drawn at
valina [46]

Answer:

P(Same)=\frac{61}{190}

Step-by-step explanation:

Given

Red = 5

White = 6

Black = 9

Required

The probability of selecting 2 same colors when the first is not replaced

The total number of ball is:

Total = 5 + 6 + 9

Total = 20

This is calculated as:

P(Same)=P(Red\ and\ Red) + P(White\ and\ White) + P(Black\ and\ Black)

So, we have:

P(Same)=\frac{n(Red)}{Total} * \frac{n(Red) - 1}{Total - 1} + \frac{n(White)}{Total} * \frac{n(White) - 1}{Total - 1}  + \frac{n(Black)}{Total} * \frac{n(Black) - 1}{Total - 1}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

P(Same)=\frac{5}{20} * \frac{5 - 1}{20- 1} + \frac{6}{20} * \frac{6 - 1}{20- 1}  + \frac{9}{20} * \frac{9- 1}{20- 1}

P(Same)=\frac{5}{20} * \frac{4}{19} + \frac{6}{20} * \frac{5}{19}  + \frac{9}{20} * \frac{8}{19}

P(Same)=\frac{20}{380} + \frac{30}{380}  + \frac{72}{380}

P(Same)=\frac{20+30+72}{380}

P(Same)=\frac{122}{380}

P(Same)=\frac{61}{190}

4 0
3 years ago
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