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3 years ago

1 find the area in square cm of a square whose side is

Mathematics

2 answers:

Mila [183]3 years ago

4 0

Answer:

Step-by-step explanation:

i) Area of Square = Length^{2}

= 2.6 × 2.6 = 6.76 cm^{2}

ii)

1 dm = 10 cm

1.2 dm = 12cm

Area of Square = 12×12 = 144 cm

1 dm = 0.1 m

16.5 dm = 1.65 m

Area of square = 1.65×1.65 = 2.7225 m^2

= 2.7225 sq m

lara [203]3 years ago

3 0

For question 1:

Part i)

2.6 x 2.6 = 6.76 cm squared

No unit conversions needed

Part ii)

1.2 dm = 1.2 / 1000000 = 0.0000012 cm

0.0000012 x 0.0000012 = 0.00000000000144 cm squared

Question 2:

16.5dm = 16.5/ 1000 = 0.0165 m

0.0165 x 0.0165 = 0.00027225 m squared

I hope this has helped

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Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

horsena [70]

Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

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Step-by-step explanation:

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Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

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A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is: