A lock has a code of 3 numbers between 1 and 25. If no numbers in the code are allowed to repeat, how many different codes could
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Answer:
22
Step-by-step explanation:
Find f(-3) :
f(x) = x² + 2x for x ≤ -3
That means for those values of x, less than or equal to -3, this is the function.
So, f(-3) = (-3)² + 2(-3) = 9 - 6 = 3
Now, f(-1) :
From the given data, we see it is: f(x) = 2
We take this because -1 lies between -3 and 4.
Now, f(-1) = 2
=>
For f(4) :
Clearly, the function is:
Therefore, <u>f(-3) + f(-1) - f(4) = 3 + 18 - (-1) = 3 + 18 + 1 = 22.</u>
