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Ahat [919]
3 years ago
13

A lock has a code of 3 numbers between 1 and 25. If no numbers in the code are allowed to repeat, how many different codes could

be made?
Mathematics
1 answer:
Sloan [31]3 years ago
6 0
12167 codes can be made
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Can someone help I need this asap
balu736 [363]

Answer:

Step-by-step explanation:

Total number of students =100

Number who bought pop corn = 62

Number who bought drinks = 47

Number who bought both =38

Hence number who did not purchase anything = 100-(62+47-38)

=29

Prob that students buys a drink = 47/100 = 0.47

PROB THAT THE  student buys a drink/he purchsaed pop corn

= Number for both/number of pop corn

=38/62 =0.613

P(buying pop corn) = 0.62 and P(drink) = 0.47

Product of these = 0.62*0.37=0.2356

Thus we find product is not equal to Prob of purchsing both

Hence cannot be independent

4 0
3 years ago
An IV infiltrates with 330 mL remaining in the bag. It was restarted at 1015 at a rate of 30 mL/hr. What is the IV completion ti
DochEvi [55]

Answer:

11 hours

Step-by-step explanation:

I came up with this answer by dividing the IV infiltrate in the bag by the rate. This gave the completion time.

Volume of IV infiltrate = 330ML

Rate at which it was running = 30 ML/hour

The IV completion time = volume/rate

= 330 ML/30 ML

= 11 hours

Therefore the IV completion time is 11 hours.

3 0
3 years ago
PLEASE LEND ME A HAND! I NEED IT BADLY!!!
V125BC [204]

Answer:

The first one is A

The second one is B

3 0
3 years ago
Read 2 more answers
Curtis threw 15 darts at a dartboard.40% of his darts hit the bull’s eye.how many darts not hit the bulls eye?
Harlamova29_29 [7]

Answer:

9

Step-by-step explanation:

The number of darts that failed to hit the bulls eye is 40% of 15 subtracted from 15

Since 40% of the darts hit the bulls eye .

Therefore

40% of 15

40/100 x 15

0.4 x 15

6

This means that 6 darts hit the bulls eye.

Therefore,number of darts that did not hit the bulls eye is

15 - 6 = 9

9 darts failed to hit the bulls eye

7 0
3 years ago
Which expression is equivalent
Tatiana [17]

Given expression is

\sqrt[4]{\frac{16x^{11}y^8}{81x^7y^6}}

Radical is fourth root

first we simplify the terms inside the radical

\frac{x^{11}}{x^7}=x^4

\frac{y^(8)}{y^6}=y^2

So the expression becomes

\sqrt[4]{\frac{16x^4y^2}{81}}

Now we take fourth root

\sqrt[4]{16} = 2

\sqrt[4]{81} = 3

\sqrt[4]{x^4} = x

We cannot simplify fourth root (y^2)

After simplification , expression becomes

\frac{2x\sqrt[4]{y^2}}{3}

Answer is option B


8 0
3 years ago
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