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Stolb23 [73]
4 years ago
8

Which of the following about the normal distribution is not​ true? A. ​Theoretically, the​ mean, median, and mode are the same.

B. Its parameters are the​ mean, mu​, and standard​ deviation, sigma. C. About two thirds of the observations fall withinplus or minus1 standard deviation from the mean. D. It is a discrete probability distribution.
Mathematics
1 answer:
sweet [91]4 years ago
7 0

Answer:

Statement A and C are true about the normal distribution.

Step-by-step explanation:

We have to identify true statements for normal distribution.

A) True

The mean, median and mode for a normal distribution are same

B) False

The parameters of normal distribution are mean and the standard deviation.

C) True

According to Empirical rule for normal distribution  about two-third of data lies within plus or minus one standard deviation from the mean.

D) False

Normal distribution is a continuous probability distribution.

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MA_775_DIABLO [31]
F'(x)=-2x{e^(-x²)}
Equating f'(x)=0,
i.e,

-2x{e^(-x²)}=0....eqn(i)
For maximum slope:
Differentiating (i) wrt x,we get,
4x² {e^(-x²)}-2 {e^(-x²)}=0
{e^(-x²)} [4x²-2]=0
4x²-2=0
x=1/√2

If f(x)=y then f'(x)=dy/dx=slope
So,
Maximum slope
= f'(x)
= -2x{e^(-x²)}
=-2×(1/✓2){e^(-1/✓2)²}
= -✓2{e^(-1/2)}
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6 0
3 years ago
What is the perimeter of a square of the side length is 3 cm
murzikaleks [220]

Answer:

Perimeter  = 12

Step-by-step explanation:

Perimeter of a square:  P = 4(s)

P = Perimeter

S = side

<u>Step 1:</u>  Calculate

P = 4(3)

P = 12

7 0
4 years ago
A jar contains sugar. The jar and the sugar have a total weight of 850 g. Anna uses 2/3 of the sugar. The jar and the sugar now
maria [59]

Answer:

J = 370g

Step-by-step explanation:

Given

Represent the weight of the Jar with J and the sugar with S

Initially, we have:

J + S = 850g

After 2/3 of sugar is removed we have:

J + S -\frac{2}{3}S= 530g

Required

Determine the weight of the jar

J + S = 850g --- (1)

J + S -\frac{2}{3}S= 530g --- (2)

Simplify (2)

J + S -\frac{2S}{3}= 530g

Take LCM

J + \frac{3S - 2S}{3}= 530g

J + \frac{S}{3}= 530g

Make S the subject in (1)

J + S = 850g

S = 850g - J

Substitute 850g - J for S in J + \frac{S}{3}= 530g

J + \frac{850g - J}{3}= 530g

Multiply through by 3

3 * J + 3*\frac{850g - J}{3}= 530g * 3

3J + 850g - J= 1590g

Collect Like Terms

3J  - J= 1590g-850g

2J= 740g

Make J the subject

J = \frac{1}{2} * 740g

J = 370g

<em>The jar weighs 370g</em>

5 0
3 years ago
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the answer to this question is D

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