What pair of fractions? I will be able to help i just need to know what fractions to use :)
Answer:
2
Step-by-step explanation:
The first equation is that of a an ellipse. The second equation is that of a line.
Attached is the graphs of both of these equations.
<em>If you think about it, there can only be 2 possible ways of solutions (intersection points) of an ellipse and a line.</em>
<em>1. The line will not intersect the ellipse at all, so no solution</em>
<em>2. The line will intersect the ellipse at 2 points maximum</em>
<em />
So, we can clearly see from the reasoning that the maximum number of possible solutions would be 2. The graph attached confirms this as well.
Answer:
The y intercept, (0,400) represents the amount of money the radio station originally had. The x-intercept, (8,0), represents the amount of weeks it will take for the radio station to have $0 left.
Step-by-step explanation:
We can find this using the formula: L= ∫√1+ (y')² dx
First we want to solve for y by taking the 1/2 power of both sides:
y=(4(x+1)³)^1/2
y=2(x+1)^3/2
Now, we can take the derivative using the chain rule:
y'=3(x+1)^1/2
We can then square this, so it can be plugged directly into the formula:
(y')²=(3√x+1)²
<span>(y')²=9(x+1)
</span>(y')²=9x+9
We can then plug this into the formula:
L= ∫√1+9x+9 dx *I can't type in the bounds directly on the integral, but the upper bound is 1 and the lower bound is 0
L= ∫(9x+10)^1/2 dx *use u-substitution to solve
L= ∫u^1/2 (du/9)
L= 1/9 ∫u^1/2 du
L= 1/9[(2/3)u^3/2]
L= 2/27 [(9x+10)^3/2] *upper bound is 1 and lower bound is 0
L= 2/27 [19^3/2-10^3/2]
L= 2/27 [√6859 - √1000]
L=3.792318765
The length of the curve is 2/27 [√6859 - √1000] or <span>3.792318765 </span>units.
