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slega [8]
3 years ago
13

Which exponent makes the statement true? 1 --- = 5 (?) (9) 5 (properties of exponents)?

Mathematics
1 answer:
Allushta [10]3 years ago
7 0
(1/5)^9 
<span>= 5^-9 
so the correct option is 
-9
it will be B 
hope it helps</span>
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Suppose the average yearly salary of an individual whose final degree is a​ master's is ​$43 thousand less than twice that of an
natka813 [3]

Answer:

A person who holds a master's degree would earn an average $63,000

A person who holds a bachelor's only would earn an average $53,000

Step-by-step explanation:

We will need to construct equations from the sentences.

Firstly, let the yearly average for a master's degree holder be m and that of bachelor's be b.

Now, we know that someone with a master's earn 43000 less than twice what someone with bachelors earn.

Mathematically,

m = 2b - 43,000

Combined, they have an average salary of 116,000

Mathematically,

m + b = 116,000

Now we have 2 equations to solve simultaneously.

m = 2b - 43,000 ......(i)

m + b = 116,000 .......(ii)

We can sub I into ii

2b - 43,000 + b = 116,000

2b+b = 116,000 + 43,000

3b = 159,000

b = 159,000/3 = 53,000

m = 2b - 43,000

m = 2(53,000) - 43,000 = 63,000

6 0
3 years ago
. A fraction becomes 4 if one is added to both numerator and the denominator If 5 is subtracted from 5
kari74 [83]

the answer is 7/9. ...........

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3 years ago
I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t
belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}

Where

\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}

Thus,

\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}

thus, BC = 7.5

2) BX = 9, BA = 15, BY = 15, YC = y

In the above diagram,

\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}

Thus, from the theorem of similar triangles,

\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}

solving for y, we have

\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}

thus, YC = 10.

4 0
1 year ago
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