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Y_Kistochka [10]
3 years ago
8

What is the pattern? 1, 4, 2, 8, 4, 16, 8, 32, ... _____

Mathematics
2 answers:
Verdich [7]3 years ago
7 0

Answer:

The pattern is multiply by 4 then divide by 2.

Step-by-step explanation:

1, 4, 2, 8, 4, 16, 8, 32, 16, 64, 32, 128... So on, So on

They are multiplying by 4 then dividing by 2, multiply by 4, divide by 2... so on, so on

Pachacha [2.7K]3 years ago
5 0

Answer:

multiply by 4 divide by 2

Step-by-step explanation:

You might be interested in
Solve for x.<br> Can anyone help me please?
bixtya [17]

Answer:

The answer is 1

Step-by-step explanation:

3-4= -1

-1+x= 1

4 0
3 years ago
A survey of 500 students in a school found that about 100 households consist of only vegetarians, 240 consist of vegetarians and
RideAnS [48]
100+160/500 consist of only vegetarians, or only non-vegetarians, which equal 260/500=13/25 probability. ☺☺☺☺
4 0
4 years ago
Jade’s weekly paycheck is $306.25. She makes $8.75 per hour. Divide to find the number of hours per week Jade works.
ZanzabumX [31]

So if Jade makes $306.25 a week and for every hour she works, she makes $8.75, then all you have to do is divide 306.25 by 8.75.

306.25/8.75 = 35 hours should be your answer

Let me know if that doesn't make sense or you still don't understand it :)

5 0
3 years ago
Read 2 more answers
What is the correct answer?
Tasya [4]

Given:

The function is

f(x)=(x+3)^2(x-5)^6

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}       ...(i)

where, a is a constant, c_1,c_2,...,c_n are zeros of respective multiplicities m_1,m_2,...,m_n.

We have,

f(x)=(x+3)^2(x-5)^6

On comparing this with (i), we get

c_1=-3,m_1=2

c_2=5,m_2=6

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

5 0
3 years ago
According to the Vivino website, suppose the mean price for a bottle of red wine that scores 4.0 or higher on the Vivino Rating
Natali [406]

Answer:

a) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

b) Test statistic t=-1.565

P-value = 0.0612

NOTE: the sample size is n=65.

c) Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

d) Null and alternative hypothesis

H_0: \mu=32.48\\\\H_a:\mu< 32.48

Test statistic t=-1.565

Critical value tc=-1.669

t>tc --> Do not reject H0

Do not reject H0. We cannot conclude that the price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

Then, the null and alternative hypothesis are:

H_0: \mu=32.48\\\\H_a:\mu< 32.48

The significance level is 0.05.

The sample has a size n=65.

The sample mean is M=30.15.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{65}}=1.4884

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{30.15-32.48}{1.4884}=\dfrac{-2.33}{1.4884}=-1.565

The degrees of freedom for this sample size are:

df=n-1=65-1=64

This test is a left-tailed test, with 64 degrees of freedom and t=-1.565, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t

As the P-value (0.0612) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

At a significance level of 0.05, there is not enough evidence to support the claim that the mean price in Providence for a bottle of red wine that scores 4.0 or higher on the Vivino Rating System is less than the population mean of $32.48.

<u>Critical value approach</u>

<u></u>

At a significance level of 0.05, for a left-tailed test, with 64 degrees of freedom, the critical value is t=-1.669.

As the test statistic is greater than the critical value, it falls in the acceptance region.

The null hypothesis failed to be rejected.

6 0
3 years ago
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