Question

The edge of a flying disc with a radius of 0.13 m spins with a tangential speed of 3.3 m/s.

Answer 1

A = v²/r

v = 3.3 m/s
r = 0.13 m

a: centripetal acceleration

Answer 2

By definition, centripetal acceleration is given by:

$a = \frac{v ^ 2}{r}$

Where,

v: tangential disk speed

r: disk radius

Substituting values in the given equation we have:

$a =\frac{3.3^2}{0.13}\\a = 83.76923077$

Rounding the result we have:

$a = 83.8 \frac{m}{s^2}$

Answer:

The centripetal acceleration of the disc edge in m/s^2 is:

$a = 83.8 \frac{m}{s^2}$