I think it’s A I got that off the information I got in the internet
Answer
given,
angular speed of the tub = 5 rev/s
time = 9 s
he tub slows to rest = 15.0 s
the angular acceleration



angular displacement




case 2
now,


time = 15 s
the angular acceleration



angular displacement




total revolution in 24 s
= 23 + 38
= 62 revolution
Yes they should all be going the same speed.
Hope this helped :)
Answer:
1320336992.2512 m²
1320.33 kilometers or 509.79 miles
Explanation:
Energy transferred by the sun

Energy required by the United States is
(assumed)
Power

Area

Area of the solar collector would be 1320336992.2512 m²
Converting to km²


Converting to mi²


Each side of the square would be 1320.33 kilometers or 509.79 miles
The direction of the deflection on the screen caused by the vertical component of the Earth's magnetic field, taken as 20.0uT down is 6.3445*10^-16
Given,
E = Accelerating voltage = 2.47×10³ V
m = Mass of electron
Distance electron travels = 33.5 cm = 0.335 cm
By using the formula,
E = mv^2 /2
v = 
v = 
v = 29455256.08671 m/s
Deflection by Earth's Gravity
Δ = g s^2/v^2 / 2
Δ = 9.81
/ 2
Δ = 6.3445 * 10^-16 m
Therefore,
Magnitude of the direction on the screen caused by the Earth's Magnetic field is 6.3445*10-16 m
To know more about "Magnetic field"
Refer this link:
https://brainly.in/question/261007?referrer=searchResults
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