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3 years ago

What is free nitrogen

Physics

2 answers:

Sati [7]3 years ago

6 0

Answer:

It is molecule nitrogen N2.

Explanation:

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Alenkasestr [34]3 years ago

4 0

Answer:

It is simply molecular nitrogen (N2). Nitrogen, in its molecular form, consists of two nitrogen atoms bound together with a tripple bond

Explanation:

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Imagine another solar system, with a star of the same mass as the Sun. Suppose a planet with a mass twice that of Earth (2 Earth

sashaice [31]

Answer:

Time period, T = 403.78 years

Explanation:

It is given that,

Orbital distance, $a=1\ AU=1.496\times 10^{11}\ m$

Mass of the Earth, $m_e=5.972\times 10^{24}\ kg$

Mass of the planet, $m_p=2m_e=11.944\times 10^{24}\ kg$

Let T is the orbital period of this planet. The Kepler's third law of motion gives the relation between the orbital period and the orbital distance.

$T^2=\dfrac{4\pi^2}{Gm_p}a^3$

$T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 11.944\times 10^{24}}\times (1.496\times 10^{11})^3$

$T=1.28\times 10^{10}\ s$

T = 403.78 years

So, the orbital period of this planet is 404 years. Hence, this is the required solution.

4 0

3 years ago

A car accidently rolls off acliff. As it leaves the cliff it has a horizontal of 13m/s, it hits they ground 60m from the shoreli

zimovet [89]

Answer:

jsudyve elected

Explanation:

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3 years ago

3. A (n) __ stores food or water in a cell

pishuonlain [190]

A vacuole stores water and food in a cell

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3 years ago

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Bob is watching Anna fly by in her new high-speed plane, which Anna knows to be 60 m in length. As a greeting, Anna turns on two

vlada-n [284]

Answer:

0.196*c

Explanation:

A good thing to remember is that once you have the position and the time in one frame we can figure out corresponding position and time in another frame in other frames given their relative velocities.

Anna moves in (S') frame and we are given two events synchronized in her frame with the distance between them, Hence using Lorentz transformation to show which event Bob frame (S) will see first:

Hence,

$dt = y (dt' + \frac{v*dx}{c^2} ) \\\\dt' = 0\\dx' = 60 m\\\\t_2 - t_1 = \sqrt{\frac{1}{(1 - v^2/c^2) } } * (\frac{v*(x_2 - x_1)}{c^2} )$

we are assuming that dx' > 0 , hence we are saying that light emitted from front end of the plane is event number two and that coming from the back end is event number one. As the time in Bob's frame turns out to be positive, this means that event number two happened after event number one in his frame, in other words, the light emitted from the back end of Anna's plane arrives first to Bob's eyes.

Given:

dt' = 40ns

dt = 0

dx' = 60

Solution:

$dt' = \sqrt{\frac{1}{(1 - v^2/c^2) } } * (\frac{v*dx'}{c^2} )\\\\\sqrt{1 - \frac {v^2}{c^2 } } = (\frac{v*dx'}{c^2*dt} )\\\\v^2 = \frac{c^4*dt^2}{c^2*dt^2 + dx'^2}\\\\v = \frac{c^2*dt}{\sqrt{c^2*dt^2 + dx'^2} }\\\\v = \frac{(3*10^8)^2*40*10^9}{\sqrt{(3*10^8)^2*(40*10^9)^2 + 60^2} }\\\\v = \frac{3.6*10^9}{61} \\\\v = 0.196 c$

8 0

3 years ago

Is the trachea stiff or flexible

Whitepunk [10]

Answer:flexible

Explanation:In the trachea, or windpipe there are tracheal rings, also known as tracheal cartilage. cartilage is strong with flushable tissue. The tracheal cartilages help support the trachea while still allowing it to move and flex during breathing.

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3 years ago