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Katyanochek1 [597]
3 years ago
14

What is free nitrogen

Physics
2 answers:
Sati [7]3 years ago
6 0

Answer:

It is molecule nitrogen N2.

Explanation:

Plz mark as brainliest

Alenkasestr [34]3 years ago
4 0

Answer:

It is simply molecular nitrogen (N2). Nitrogen, in its molecular form, consists of two nitrogen atoms bound together with a tripple bond

Explanation:

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The bending of wave crests as the reach shallow water is:
Blizzard [7]
Idk can u say it in a another way
5 0
3 years ago
Which term describes a substance that has a low melting point and poor electrical conductivity?
densk [106]

Answer:Simple Covalent substance

Explanation:Simple covalent substance describes a substance that has a low melting point and poor electrical conductivity because:

(1)melting point :For the covalent bond and intermolecular force that are present in a simple covalent substance,energy is needed to break the forces of attraction present. In the simple covalent substance, little energy is needed because the intermolecular forces present are broken because they are weaker compared to the covalent bond present.

Therefore, when simple covalent substance melts,only the intermolecular forces are broken leaving only the covalent bond in the substance.

(2) poor conductivity: for a substance to conduct electricity,it must have charged particles which are free to move to and fro.

But in the simple covalent substance,there are no charged particles that can be separated due to the covalent bond present in simple covalent substance.

4 0
3 years ago
Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constan
elena55 [62]

Answer:

10.07m/s^2

Explanation:

Information we have:

velocities:

initial velocity: v_{i}=0mph (starts from rest)

final velocity: v_{f}=50mph

time:  t=2.22s

Since we need the answer in m/s^2, we nees to convert the speed to meters per second:

v_{f}=\frac{50miles}{1hour}(\frac{1hour}{3,600s} )(\frac{1609.34meters}{1mile} ) \\\\v_{f}=\frac{50*1609.34}{3600} m/s\\\\v_{f}=22.35m/s

We find the acceleration with the following formula:

a=\frac{v_{f}-v_{i}}{t}

substituting the known values:

a=\frac{22.35m/s-0m/s}{2.22s}\\ \\a=10.07m/s^2

the acceleration is 10.07m/s^2

8 0
2 years ago
Read 2 more answers
An aerobatic airplane pilot experiences weightlessness as she passes over the top of a loop-the-loop maneuver. the acceleration
Yanka [14]
The acceleration due to gravity serves as the centripetal acceleration of the objects that orbits the Earth. The centripetal acceleration due to gravity is calculated through the equation,

    a = v²/r

where v is the speed and r is the radius. Substituting the known values to the equation,

   9.8 m/s² = (420 m/s)² / r

The value of r from the equation is 18000 m or equal to 18 km.

<em>Answer: 18 km</em>
6 0
3 years ago
Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light.
pogonyaev

Complete Question

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light

Answer:

The diameter is  D = 0.59 \  m    

Explanation:

From the question we are told that

      The best resolution is  \theta  =  0.3 \  arcsecond

       The  wavelength is  \lambda  =  700 \  nm =  700 *10^{-9 } \  m

       

Generally the

         1 arcminute  = >  60 arcseconds

=>      x arcminute =>   0.3 arcsecond

So

       x =  \frac{0.3}{60 }

=>    x = 0.005 \  arcminutes

Now

         60 arcminutes  =>  1 degree

          0.005 arcminutes = >  z degrees  

=>       z =  \frac{0.005}{60 }

=>      z =  8.333 *10^{-5}  \ degree

Converting to radian  

           \theta  = z =  8.333 *10^{-5}  * 0.01745 = 1.454 *10^{-6} \  radian

Generally the resolution is mathematically represented as

            \theta  =  \frac{1.22 *  \lambda  }{ D}

=>    D =  \frac{1.22 * \lambda }{\theta }

=>     D =  \frac{1.22 * 700 *10^{-9} }{ 1.454 *10^{-6} }    

=>     D = 0.59 \  m    

4 0
2 years ago
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