Answer:
(a) X electrode
(b) Y electrode
(c) Y electrode
(d) X electrode
(e) Y electrode
Explanation:
<em>A galvanic (voltaic) cell has the generic metals X and Y as electrodes. X is more reactive than Y, that is, X more readily reacts to form a cation than Y does.</em>
In the X electrode occurs the oxidation whereas in the Y electrode occurs the reduction.
Oxidation: X(s) → X⁺ⁿ(aq) + n e⁻
Reduction: Y⁺ˣ(aq) + x e⁻ → Y(s)
<em>Classify the descriptions by whether they apply to the X or Y electrode.
</em>
<em>(a) anode.</em> Is where the oxidation takes place (X electrode).
<em>(b) cathode.</em> Is where the reduction takes place (Y electrode).
<em>(c) electrons in the wire flow toward.</em> Electrons in the wire flow toward the cathode (Y electrode).
<em>(d) electrons in the wire flow away.</em> Electrons in the wire flow away from the anode (X electrode).
<em>(e) cations from salt bridge flow toward.</em> Cations from the salt bridge flow toward the cathode (Y electrode) to maintain the electroneutrality.
A-Aluminium sulphate.
B-Calcium Chloride.
C-Potassium sulphate.
D-Potassium Nitrate .
E-Calcium Carbonate.
Explanation:
everything can be found in the picture
In electrophilic aromatic substitution reactions the hydroxyl group is an o,p-director because: hydroxyl group donates the electron density to the ring by induction and destabilizes the meta sigma complex and by resonance and it stabilizes the ortho and para sigma complexes of aromatic ring .
Most ring activators have atoms with unshared electron pairs directly attached to a carbon atom of the benzene ring . For example, the — OH group has two pairs of unshared electrons on the oxygen atom , which will form a bond to a carbon atom of the benzene ring . Thus , the — OH group will be an activating group in electrophilic aromatic substitution reactions .
to learn more about electrophilic aromatic substitution reactions please click here ,
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Answer:
6.178 g.
Explanation:
- KCl is ionized in the solution as:
<em>KCl → K⁺ + Cl⁻.</em>
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∴ [KCl] = [K⁺] = [Cl⁻] = 0.193 M.
<em>Molarity is defined as the no. of moles of the solute per 1.0 L of the solution.</em>
<em />
∵ M = [(mass/molar mass)KCl][(1000)/(V of the solution)].
<em>∴ mass of KCl = (M)(molar mass of KCl)(V of the solution)/1000</em> = (0.193 M)(74.55 g/mol)(430.0 mL)/1000 = <em>6.178 g.</em>
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