Answer:
Mass of benzene required = 0.78 g
Explanation:
Given data:
Mass of CO₂ produced = 2.66 g
Mass of benzene required = ?
Solution:
Chemical equation:
2C₆H₆ + 15O₂ → 6H₂O + 12CO₂
Number of moles of CO₂:
Number of moles = mass/molar mass
Number of moles = 2.66 g/ 44 g/mol
Number of moles = 0.06 mol
Now we will compare the moles of CO₂ with C₆H₆.
CO₂ : C₆H₆
12 : 2
0.06 : 2/12×0.06=0.01 mol
Mass of benzene required:
Mass = number of moles × molar mass
Mass = 0.01 mol × 78.11 g/mol
Mass = 0.78 g
