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slamgirl [31]
3 years ago
12

Find the mass of benzene (C6H6) required to produce 2.66 g of carbon dioxide gas from the reaction described by the following eq

uation:
2C6H6 + 15O2 → 6H2O + 12CO2
Chemistry
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

Mass of benzene required = 0.78 g

Explanation:

Given data:

Mass of CO₂ produced = 2.66 g

Mass of benzene required = ?

Solution:

Chemical equation:

2C₆H₆ + 15O₂       →    6H₂O + 12CO₂

Number of moles of CO₂:

Number of moles = mass/molar mass

Number of moles = 2.66 g/ 44 g/mol

Number of moles = 0.06 mol

Now we will compare the moles of CO₂ with C₆H₆.

                        CO₂       :        C₆H₆

                            12        :          2

                          0.06      :        2/12×0.06=0.01 mol

Mass of benzene required:

Mass = number of moles × molar mass

Mass = 0.01 mol × 78.11 g/mol

Mass = 0.78 g

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URGENT !! A substance has 55.80% carbon, 7.04% Hydrogen, and 37.16% Oxygen. What is it's empirical and molecular formula if it h
Ede4ka [16]
<h3><u>Answer;</u></h3>

Empirical formula = C₂H₃O

Molecular formula = C₁₄H₂₁O₇

<h3><u>Explanation</u>;</h3>

Empirical formula

Moles of;

Carbon = 55.8 /12 = 4.65 moles

Hydrogen = 7.04/ 1 = 7.04 moles

Oxygen  = 37.16/ 16 = 2.3225 moles

We then get the mole ratio;

4.65/2.3225 = 2.0

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4 years ago
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