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3 years ago

Equivalent ratio

Mathematics

1 answer:

Svetradugi [14.3K]3 years ago

6 0

Answer:

D.) 1:6

E.) 8:48

Step-by-step explanation:

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Math help !! :) thanks!

Ber [7]

X= (-7,12)

Y= (7,-9)

The distance between the x points is 14 units

we want a ratio of 3 to 4

for every 3 on one side there are 4 on the other for 7 total

6 to 8 = 14

so 6 on one side 8 on the other

so 6 units on the left starting at -7

-7 + 6 = -1

same with y

12 to -9 is 21 units

3 to 4 = 7

6 to 8 =14

9 to 12 = 21

so 9 unit from the top

12-9 = 3

(-1,3)

Choice A

5 0

2 years ago

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A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar

zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a $Pr = \frac{2}{110}$

b $Pr = \frac{72}{110}$

Step-by-step explanation:

Given

$n = 11$ --- hammers

$r = 2$ --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

$Pr = P(D) * P(D)$

$Pr = \frac{2}{11} * \frac{2-1}{11-1}$

$Pr = \frac{2}{11} * \frac{1}{10}$

$Pr = \frac{2}{110}$

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

$P(D') = \frac{9}{11}$

For two selections, the probability that all are not defective is:

$Pr = P(D') * P(D')$

$Pr = \frac{9}{11} * \frac{9-1}{11-1}$

$Pr = \frac{9}{11} * \frac{8}{10}$

$Pr = \frac{72}{110}$

8 0

2 years ago

1. Which of the following values of n will make the below equation true? n × (−2+5 ) = −8+20

Salsk061 [2.6K]

Answer:

1a 2a

Step-by-step explanation:

n × (−2+5 ) = −8+20

n × 3 = 12

n = 4

2 + (n+6) = −1+6

n + 8 = 5

n = -3

7 0

2 years ago

Triangles Unit Test part 1 A length of rope is stretched between the top edge of a building and a stake in the ground. The head

musickatia [10]

Answer:

The building is 32 feet tall.

Step-by-step explanation:

Consider the figure drawn below representing the given scenario.

AB represents the height of building, BC is the distance between the stake and building, C represents the stake at ground level, and DE represents the height of the tree growing halfway between building and stake.

Since the tree is growing halfway between B and C, therefore, the point E divides the line segment BC into 2 equal parts.

Therefore, $BE = EC$ or E is the midpoint of BC.

Also, from the figure, it is clear that both tree and building are vertical to the ground. So, DE || AB.

Now, from converse of mid-segment theorem, if a line passes through the midpoint of one side of a triangle and also parallel to the third side, then the line also passes through the midpoint of the second side and half the length of the third side (parallel side)

So,

$DE=\frac{1}{2}\times AB\\\\16=\frac{AB}{2}\\\\AB=16\times 2=32\ ft$

Therefore, the building is 32 feet tall.

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2 years ago

A survey reported that 713,298 people visited the local science museum last year. How can 713,298 be written in word form?

AnnZ [28]

Seven hundred and thirteen thousand, two hundred and ninety eight

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2 years ago

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