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a_sh-v [17]
3 years ago
6

What is the answer 1/3x+y=4 Y=

Mathematics
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

{ \tt{ \frac{1}{3} x + y = 4}} \\  \\ → \: { \tt{y = 4 -  \frac{1}{3} x}}

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Find the larger of the two roots of the equation y = -2.2x2 + 63.5x - 17
Luden [163]

The larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

<h3>How to find the roots of a quadratic equation?</h3>

Suppose that the given quadratic equation is

ax^2 + bx + c = 0

Then its roots are given as:

x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The given quadratic equation is

y = -2.2x^2 + 63.5x - 17

now, the roots of the equation are

x = \dfrac{-63.5 \pm \sqrt{63.5^2 - 4(-2.2)(-17)}}{2(-2.2)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{4032.25 - 149.6}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm \sqrt{3882.65}}{(-4.4)}\\\\\\x = \dfrac{-63.5 \pm 62.31}{(-4.4)}

The two roots are 0.27 and 28.59.

Thus, the larger of the two roots of the equation y = -2.2x^2 + 63.5x - 17would be 28.59.

Learn more about finding the solutions of a quadratic equation here:

brainly.com/question/3358603

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7 0
2 years ago
Please help with 7-9 they are related to the same circle
Andrej [43]

40º

7) In this problem, we can see that both tangent lines to that circle come from the same point O.

So, we can write out the following considering that there is one secant line DO and one tangent line to the circle AO

\begin{gathered} m\angle1=\frac{1}{2}(160-80) \\ m\angle1=\frac{1}{2}(80) \\ m\angle1=40^{\circ} \end{gathered}

3 0
1 year ago
During an April rainstorm, it rained for six straight days. The amount of rainfall for each day was 0.8 inch, 2.15 inches, 2 inc
Andrei [34K]

Answer:

6.12 inches

Step-by-step explanation:


4 0
3 years ago
Read 2 more answers
2+2=?<br> and it's not 4. :)
Sindrei [870]

Answer:

a carrot? yea a carrot. :D

8 0
3 years ago
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PLSSSSSSSSSSS HELPPP&gt;&gt; Show work solve the sysytem- y=1/2x^2+4x+4 y=-4x+12 1/2
Mrac [35]

Answer:

(1, 8.5 ) and ( - 17, 80.5 )

Step-by-step explanation:

Given the 2 equations

y = \frac{1}{2} x² + 4x + 4 → (1)

y = - 4x + 12 \frac{1}{2} → (2)

Substitute (1) into (2), that is

\frac{1}{2} x² + 4x + 4 = - 4x + 12 \frac{1}{2} ( multiply through by 2 to clear the fractions )

x² + 8x + 8 = - 8x + 25 ( add 8x to both sides )

x² + 16x + 8 = 25 ( subtract 25 from both sides )

x² + 16x - 17 = 0 ← in standard form

(x + 17)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 17 = 0 ⇒ x = - 17

x - 1 = 0 ⇒ x = 1

Substitute these values into either of the 2 equations and evaluate for y

Substituting into (2 )

x = 1 : y = - 4(1) + 12.5 = - 4 + 12.5 = 8.5 ⇒ (1, 8.5 )

x = - 17 : y = - 4(- 17) + 12.5 = 68 + 12.5 = 80.5 ⇒ (- 17, 80.5 )

5 0
3 years ago
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