Answer: You need to show us the models.
Step-by-step explanation:
please
The maximum value of the objective function is 330
<h3>How to maximize the
objective function?</h3>
The given parameters are:
Max w = 5y₁ + 3y₂
Subject to
y₁ + y₂ ≤ 50
2y₁ + 3y₂ ≤ 60
y₁ , y₂ ≥ 0
Start by plotting the graph of the constraints (see attachment)
From the attached graph, we have:
(y₁ , y₂) = (90, -40)
Substitute (y₁ , y₂) = (90, -40) in w = 5y₁ + 3y₂
w = 5 * 90 - 3 * 40
Evaluate
w = 330
Hence, the maximum value of the function is 330
Read more about objective functions at:
brainly.com/question/26036780
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Answer:
2x-3y=-6
Step-by-step explanation:
Answer:
<em><u>In the graph locate the point (3,0) and draw a line parrallel to Y-axis passing through (3,0) .</u></em>
<em><u>Then your line will cut the graph of f(x) at some point, that point's y-coordinate will be your value of f(3).</u></em>
Step-by-step explanation:
Hope it helps!
The answer is B)
x2+2x−3=0
Factor left side of equation.
(x−1)(x+3)=0
Set factors equal to 0.
x−1=0 or x+3=0
x=1
or
x=−3