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Minchanka [31]
3 years ago
11

Crash testing is a highly expensive procedure to evaluate the ability of an automobile to withstand a serious accident. A simple

random sample of 13 small cars were subjected to a head-on collision at 40 miles per hour. Of them 8 were “totaled,” meaning that the cost of repairs is greater than the value of the car. Another sample of 17 large cars were subjected to the same test, and 5 of them were totaled. Let pX represent the population proportion of small cars that are totaled and let pY represent the population proportion of large cars that are totaled. Find a 95% confidence interval for the difference pX – pY . Round the answers to four decimal places.

Mathematics
1 answer:
gladu [14]3 years ago
5 0

Answer:

-0.0205 < p1 - p2 < 0.6631

Step-by-step explanation:

Here we need to use the formulas for a confidence interval using a difference of 2 given proportions.

Proportion 1 (small cars) = 8/13

Proportion 2 (large cars) = 5/17

A 95% confidence level has a z-score of 1.96 (the method of looking up z-scores doesn't change with using two proportions instead of 1)

See attached photo for formulas and solutions, and the construction of the confidence interval...

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What are the slope and y-intercept of the graph of this equation?
schepotkina [342]

Answer:

slope = y = 1/2

y-intercept = b = -3

Step-by-step explanation:

slope intercept equation:

y = mx + b----->(equation 1)

m is slope

b is y-intercept

y = 1/2x - 3----->(equation 2)

Compare (equation 1) and (equation 1)

slope = y = 1/2

y-intercept = b = -3

3 0
2 years ago
If tan theta = startfraction 11 over 60 endfraction, what is the value of cot theta?
Dennis_Churaev [7]

The value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

Given that trigonometric ratio:

tan\theta = \frac{11}{60}

<h3>What is the tangent of an angle?</h3>

The tangent of an angle is the ratio of the opposite side(to that angle) to the adjacent side(to that angle).

So, for the given problem

Opposite side to \theta = 11

Adjacent side to \theta = 60

So, cot \theta =\frac{AdjacentSide }{OppositeSide}

cot\theta =\frac{60}{11}

Therefore, the value of cot\theta when tan\theta =\frac{11}{60} comes to be \frac{60}{11}.

To get more about trigonometric ratios visit:

brainly.com/question/24349828

6 0
2 years ago
Makayla is working two summer jobs, making $19 per hour tutoring and making $12 per hour landscaping. In a given week, she can w
Ivanshal [37]

Answer: 12 hours

Step-by-step explanation:

3 hours landscaping = $36

She still needs to make $224 to meet her requirement.

$224 divided by $19 tutoring = 11.79 hours

224÷19=11.79

Rounded to the nearest whole number: 12

This would mean Makayla worked a total of 15 hours and made $264. Which meets her requirements.

8 0
3 years ago
A quadratic equation has a
11111nata11111 [884]

Answer:

\boxed {\boxed {\sf 2 \ real \ solutions }}

Step-by-step explanation:

The quadratic formula is:

{x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}

The discriminant of a quadratic is just the expression under the square root, or b^2-4ac. This can tell us the number of solutions a quadratic has.

If the discriminant is:

  • Positive = 2 real solutions
  • Equal to Zero = 1 real double/repeated solution
  • Negative = 0 real solutions, but 2 imaginary solutions

Our quadratic equation has a discriminant of 5, which is positive. Therefore, it has 2 real solutions.

6 0
2 years ago
Compute the multifactor productivity measure for each of the weeks shown for production of chocolate bars. What do the productiv
liq [111]

Answer:

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

Step-by-step explanation:

Computation for the multifactor productivity measure for each of the weeks shown for production of chocolate bars.

Using this formula

Week Multifactor productivity measure = (Output / Total Cost)

Where:

Output represent Quantity produced

Total cost represent Labor cost + Material cost + Overhead

Let plug in the formula

Week 1= 30,000/(40*12*6)+[(40*12*6)1.5]+(450*6)

Week 1 =30,000/(2,880)+(2,880*1.5)+2,700

Week 1 =30,000/(2,880+4,320+2,700)

Week 1=30,000/9,900

Week 1 =3.03

Week 2= 33,600/(40*12*7)+[(40*12*7)1.5]+(470*6)

Week 2 =33,600/(3,360)+(3,360*1.5)+2,820

Week 2=33,600/(3,360+5,040+2,820)

Week 2=33,600/11,220

Week 2 =2.99

Week 3= 32,200/(40*12*7)+[(40*12*7)1.5]+(460*6)

Week 3 =32,200/(3,360)+(3,360*1.5)+2,760

Week 3=32,200/(3,360+5,040+2,760)

Week 3=32,200/11,160

Week 3=2.9

Week 4= 35,400/(40*12*8)+[(40*12*8)1.5]+(480*6)

Week 4 =35,400/(3,840)+(3,840*1.5)+2,880

Week 4=35,400/(3,840+5,760+2,880)

Week 4=35,400/12,480

Week 4=2.83

Therefore the multifactor productivity measure for each of the weeks shown for production of chocolate bars is :

Week 1 =3.03

Week 2 =2.99

Week 3=2.9

Week 4=2.83

4 0
2 years ago
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