The first image has a coordinate of A'(1, 6) B'(-3, 7)
<h3>How to calculate the coordinates of an image after a translation?</h3>
Translation can be defined as movement in a straight line.
Given the rule: (x,y) → (x + 3, y - 1) and A(-2,7) B(-6,8)
That means: A(x = -2, y =7) B(x = -6, y = 8)
Thus the translation will be:
A'(-2 +3, 7-1) B'(-6+3, 8-1) = A'(1, 6) B'(-3, 7)
Therefore, the coordinate of the image is A'(1, 6) B'(-3, 7)
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Answer: 15
Step-by-step explanation: You do 60/4 to get the answer.
For this, it is kind of like a triangle and having to find the diagonal. Let's see what the two legs of the triangle would be.
Leg one= 7 units
Leg two= 8 units
8²+7²= c²
64 + 49=113
√113≈10.6
The line is 10.6 units long.
Answer:
subtract 11 from both sides
Step-by-step explanation:
-3x+11=44
-3x=33
x=-11
It's A. Y=mx+b hope this helps
