Given statement :
A certain number of children shared 63 sweets and each child gets 9 sweets.
Let x the no. of children = 
x = 
x = 7
» 7 childern
Verification :
Each child sweet × No. of children = Total no. of sweets
9 × 7 = 63
Hence proved .
5.8 = 58/10 = 29/5 ;
1.2 = 12/10 = 6/5;
(29/5) ÷ (6/5) = (29/5) × (5/6) = 29/6 = 4.83;
The correct answer os D.
Answer:
I will be answering numbers 3), 4), and 6) (so that you get most of the concept and that you are able to solve the questions by yourself), and also 9).
Step-by-step explanation:
3)
-15/4b+5/6b
So, first find the common denominator of both fractions. 4 times 6 is 24. -15/4b= -90/24b. 5/6b=20/24b. -90/24b+20/24b=-70/24b=-35/24b=-1 11/24.
4)
60m-15(4-8m)+20
What we need to do first is remove the parentheses.
60m-(15*4-15*8m)+20
=60m-60-120m+20.
So, here, we add the numbers without 'm' and the numbers with 'm.' (Always include the sign in front of the number, like in the equation, we include -60 since that's the sign in front of 60.)
60m-60-120m+20
=-60+20=-40
60m-120m=-60m
=-60m-40
6)
9y-15y+12-6y
Like I said before on number 4, we do about the exact same thing (but there are no parentheses to remove, so we skip that step.)
9y-15y+12-6y
=9y-15y-6y
=-12y+12
9)
It is basically the same thing as we did in the previous problems, just in a different way of saying it.
12x+12x+2x+2x+x+9
=28x+9 yards
Answer is C=35
How? Plug 5 into all the x's and solve for both g(x) and f(x) then finish off by subtracting f(x) from g(x).
Yes, 13•150=1950 and then 11•60=660 so combined they equal 2610
