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joja [24]
3 years ago
10

The graph represents the function a.) f(x)=-2|x|/3 b.) f(x)=-2|x| c.) f(x)=-3|x|/2 d.) f(x)=-|x|/3

Mathematics
1 answer:
inessss [21]3 years ago
8 0

ANSWER

d.

f(x) =  -  \frac{1}{3}  |x|

EXPLANATION

The parent function is

f(x)=  |x|

This function has been reflected in the x-axis and stretched horizontally.

The new equation is in the form:

f(x)=  - a |x|

The point, (3,-1) must satisfy this equation,

- 1 =  - a | 3|

3a = 1

This implies that,

a =  \frac{1}{3}

Hence the correct equation is,

f(x) =  -  \frac{1}{3}  |x|

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What is the product of all constants $k$ such that the quadratic $x^2 + kx +15$ can be factored in the form $(x+a)(x+b)$, where
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Answer:

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Step-by-step explanation:

We are given quadratic equations as

x^2+kx+15

and it can be factored as

=(x+a)(x+b)

now, we can multiply factor term

(x+a)(x+b)=x^2+(a+b)x+ab

now, we can compare

x^2+(a+b)x+ab=x^2+kx+15

so, we get

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ab=15

we are given that

'a' and 'b' are integers

so, we can find all possible factors

15=(-1\times -15),(1\times 15)

15=(-3\times -5),(3\times 5)

so, we can find k

At (-1\times -15):

k=a+b

we can plug values

k=-1-15

k=-16

At (1\times 15):

k=a+b

we can plug values

k=1+15

k=16

At (-3\times -5):

k=a+b

we can plug values

k=-3-5

k=-8

At (3\times 5):

k=a+b

we can plug values

k=3+5

k=8

So, values of k are

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We need to convert it into standard notation.

1 is in ones place, 0 is in tenths place and 2 is in hundredths place.

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So, the standard notation of 1.02×10¹ is 10.2

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