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joja [24]
4 years ago
10

The graph represents the function a.) f(x)=-2|x|/3 b.) f(x)=-2|x| c.) f(x)=-3|x|/2 d.) f(x)=-|x|/3

Mathematics
1 answer:
inessss [21]4 years ago
8 0

ANSWER

d.

f(x) =  -  \frac{1}{3}  |x|

EXPLANATION

The parent function is

f(x)=  |x|

This function has been reflected in the x-axis and stretched horizontally.

The new equation is in the form:

f(x)=  - a |x|

The point, (3,-1) must satisfy this equation,

- 1 =  - a | 3|

3a = 1

This implies that,

a =  \frac{1}{3}

Hence the correct equation is,

f(x) =  -  \frac{1}{3}  |x|

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. XYZ has vertices X (–5, 2), Y (0, –4), and Z (3, 3). What are the vertices of the image of X’Y’Z’ under the translation (x, y)
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6 0
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assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra
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Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = <em>Number of adults who use their smartphones</em>

The above situation can be represented through the binomial distribution;

P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......

where, n = number of trials (samples) taken = 15 adult smartphones

           r = number of success = at least 4

           p = probability of success which in our question is the % of adults

                 who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X \geq 4)

P(X \geq 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= 1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}

= 1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})

= <u>0.1773</u>

3 0
3 years ago
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