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sladkih [1.3K]
3 years ago
11

When evaluating the validity of a website beyond its URL, you can practice the "rule of 3" which means

Computers and Technology
2 answers:
Schach [20]3 years ago
5 0

Any information on a website should be findable within 3 mouse clicks.

Arada [10]3 years ago
3 0

When evaluating the validity of a website beyond its URL, you can practice the "Rule of 3" which means:

A. Look at 3 different pages from the same website

B. Compare 3 sources of information about the topic

C. Find 3 people in the classroom who agree with your opinion

D. Make sure that the URL for the website has 3 different extensions in it

Answer:

B. Compare 3 sources of information about the topic

Explanation:

To evaluate the validity of a website is to determine whether the website will give the needed information at that given point in time. In other words, it is the assessment of a website to know if it serves the actual purpose it claims to serve.

In order to evaluate the validity of a website, one can do the following amongst others:

1. Pick the opinions or ideas are missing

2. Consider publisher the of information

3. How professional the website looks

4. Consider the domain extension for the site

5. Look for the date of publishing

However, rule of three to evaluate the validity of a website is to then B. Compare 3 sources of information about the topic

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Two boxes overlap if their interiors have at least one point in common. Give an O(n log n)-time algorithm that decides if there
GaryK [48]

Answer:

// Program is written in C++ programming language

// The program checks if two boxes overlap and prints both boxes

// Comments are used for explanatory purpose

// Program starts here

#include<bits/stdc++.h>

#include <graphics.h>

#include <conio.h>

// Define x and y axis

struct axis { int x, y; };

bool checkRect(Axis l1, Axis r1, Axis l2, Axis r2)

{ // l1, l2, r1 and r2 represent the left and right coordinates of both rectangles

// Check one rectangle is on left side of other

if (l1.x > r2.x || l2.x > r1.x) {

return false; }

// Check if one rectangle is above other

if (l1.y < r2.y || l2.y < r1.y) {

return false; }

return true;

}

// Main Method begins here

int main()

{

// Declare integer variables to enter rectangle coordinates

// For rectangle 1

int left1, left2, right1, right2;

cout<<"Enter First rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left1;

cout<<"Bottom Left: "<<"\n";

cin>>left2;

cout<<"Top Right: "<<"\n";

cin>>right1;

cout<<"Bottom Right: "<<"\n";

cin>>right2;

// For rectangle 2

int left3, left4, right3, right4;

cout<<"Enter Second rectangle coordinates: "<<"\n";

cout<<"Top Left: "<<"\n";

cin>>left3;

cout<<"Bottom Left: "<<"\n";

cin>>left4;

cout<<"Top Right: "<<"\n";

cin>>right3;

cout<<"Bottom Right: "<<"\n";

cin>>right4;

Axis l1 = {left1, left2}, r1 = {right1, right2};

Axis l2 = {left3, left4}, r2 = {right3, right4};

if (checkRect(l1, r1, l2, r2)) {

cout<<"The Rectangles Overlap"; }

else {

cout<<"Rectangles Don't Overlap";}

// Print Rectangle 1

rectangle (left1, right1, left2, right2);

// Print Rectangle 2

rectangle (left3, right3, left4, right4);

return 0;

}

5 0
3 years ago
Write a program that takes an integer n as a parameter and sums all of the multiples of 2 or 5 from 1 to n. For example, if n =
Alex

Answer:

// here is code in c++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

// variable

int num;

int tot_sum=0;

cout<<"enter a number: ";

// read the value of n

cin>>num;

// check the multiple of 2 or 5 from 1 to n

for(int x=1;x<=num;x++)

{

// if multiple of 2 or 5 then add them

   if(x%2==0 ||x%5==0)

   {

       tot_sum=tot_sum+x;

   }

}

// print the sum

cout<<"sum of multiple of 2 or 5 is:"<<tot_sum<<endl;

return 0;

}

Explanation:

Read the number "n" from user.Check every number from 1 to n, if it is a multiple of 2 or 5 then add them to "tot_sum".When the for loop end, "tot_sum" will have sum of all the number which are either multiple of 2 or 5.Print the sum.

Output:

enter a number:11

sum of multiple of 2 or 5 is:35

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Yes definitely absolutely
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Answer:

Below is the required code:

Explanation:

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