I believe the best answer choice is A money.
I think it's A because it sounds more reasonable
<span>The formula is B.=ROUND(B3,0)
So, the format is = ROUND (cell #, # of decimal places)
well if # of decimal places is 0, it just rounds to the nearest integer.
Happy studying ^-^
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Answer: For loop
Explanation:
Using the for loop we can get the exact number of values/outcomes we require.
For example: printf(enter 20 numbers");
for(int i=0; i<20;i++)
{
scanf("%d", &number);
}
So, this is an implementation of for loop in C. Using it we can enter exact 20 numbers not less or more than that.
Therefore, for loop is the answer.
Answer:
def sum_1k(M):
s = 0
for k in range(1, M+1):
s = s + 1.0/k
return s
def test_sum_1k():
expected_value = 1.0+1.0/2+1.0/3
computed_value = sum_1k(3)
if expected_value == computed_value:
print("Test is successful")
else:
print("Test is NOT successful")
test_sum_1k()
Explanation:
It seems the hidden part is a summation (sigma) notation that goes from 1 to M with 1/k.
- Inside the <em>sum_1k(M)</em>, iterate from 1 to M and calculate-return the sum of the expression.
- Inside the <em>test_sum_1k(),</em> calculate the <em>expected_value,</em> refers to the value that is calculated by hand and <em>computed_value,</em> refers to the value that is the result of the <em>sum_1k(3). </em>Then, compare the values and print the appropriate message
- Call the <em>test_sum_1k()</em> to see the result
