Answer:
import java.util.Scanner;
public class Speed{
int speed;
public Speed(int speed){
this.speed = speed;
}
public void checkSpeed(){
if(speed >= 24 || speed <= 56){
System.out.println("Speed is normal");
}
else
System.out.println("Speed is abnormal");
}
public static void main(String...args){
Scanner input = new Scanner(System.in);
int userSpeed = 0;
System.out.println("Enter a speed: ");
userSpeed = input.nextInt();
Speed obj1 = new Speed(userSpeed)
obj1.checkSpeed();
}
Explanation:
The least common multiple (LCM) of 78, 90, and 140 is: 16,380
78 × 210 = 16,380
90 × 182 = 16,380
140 × 117 = 16,380
Answer
First part:
The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.
Second part:
The invalid bit sequence are option a. 01001000 and d. 11100111
Explanation:
Explanation for first part:
In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.
If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.
If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.
Explanation for second part:
A valid odd parity bit sequence will always have odd number of 1s.
Since in option a and d, total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.
And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.
