Question

find four consecutive integers such that three times the sum of the first and the fourth is 114 less than the product of -5 in the sum of the first two consecutive integers what are the integers ?

Answer 1

3(x + (x + 3)) + 114 = -5(x + (x + 1))
6x + 18 + 114 = -10x - 5
16x = -137
That's what I get.