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fomenos
3 years ago
12

Steve opens a bank account. The amount, in dollars, in the account x weeks after the account is opened can be modeled by functio

n f. If Steve has $5,000 in the account 20 weeks after the account is opened, which TWO of the following must be true?
Mathematics
1 answer:
ANTONII [103]3 years ago
3 0

The missing options are:

A.\ f(20) =5,000

B.\ f(5000) = 20

C. In the xy plane, point (20, 5,000) is on the graph y = f(x).

D. In the xy plane, point (5,000,20) is on the graph y = f(x)

Answer:

A.\ f(20) =5,000

C. In the xy plane, point (20, 5,000) is on the graph y = f(x).

Step-by-step explanation:

Given

Represent amount with y and weeks with x

So, we have:

x = 20 when y = 5000

Required

Select 2 correct options

A point on a graph can be illustrated using  (x,y)

So, when x = 20 and y = 5000 ----- given

(x,y) implies that:

(x,y) = (20,5000)

We got (20,5000) by substituting 20 for x and 5000 for y

<em />

<em>From the list of given options, the above represented of (x,y) is illustrated in option C</em>

Represent (x,y) as a function, we have:

y = f(x)

Substitute values for x and y

5000 = f(20)

Reorder

f(20) = 5000

<em></em>

The above is illustrated in option A

<em>Hence, A and C answers the question</em>

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faltersainse [42]

Answer:

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

2) Solution to the problem

Let X the random variable that represent the  scores on the LSAT of a population, and for this case we know the distribution for X is given by:

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We want to find a value a, such that we satisfy this condition:

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P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.35 of the area on the left and 0.65 of the area on the right it's z=-0.385. On this case P(Z<-0.385)=0.35 and P(Z>-0.385)=0.65

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Z=-0.385

And if we solve for a we got

a=150.7 -0.385*10.2=146.773

So the value of height that separates the bottom 35% of data from the top 65% (Or the 35 percentile) is 146.7.  

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