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Verizon [17]
3 years ago
10

In which of the following tissues would one expect to see a lot of tight junctions?

Biology
1 answer:
Verdich [7]3 years ago
4 0
I’d say tight epithelia has tight junctions that prevent most movement between cells
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What is an atom's atomic number?
vazorg [7]

Answer:

the number of protons in an atom

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2 years ago
The megasporangium in a pine cone is surrounded by an integument with a small opening called the?
zhannawk [14.2K]

The megasporangium in a pine cone is surrounded by an integument with a small opening called the micropyle.

Integuments in flowers are the maternal tissues or having a maternal beginning, as they originate from the ovular tissue or chalazal tissue (part of the lady reproductive gadget of a flower). A time period integument merely refers to the protecting layer. In terms of botany, an integument is a layer encircling the ovule.

A mature ovule consists of a meal tissue included by means of one or destiny seed coats, called integuments. A small establishing (the micropyle) within the integuments permits the pollen tube to enter and discharge its sperm nuclei into the embryo sac, a large oval cellular in which fertilization and improvement arise.

Learn more about integument here: brainly.com/question/2801375

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3 0
1 year ago
g If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time
Elenna [48]

Answer:

a. 8.1 milligrams

b. 40.07 hours

c. 8.859 milligrams

Explanation:

If a person takes a prescribed dose of 10 milligrams of Valium, the amount of Valium in that person's bloodstream at any time can be modeled by

A_{t}=10e^{-0.0173t}

Where A(t) = amount of Valium remaining in the blood after t hours

t = time or duration after the drug is taken

a. we have to calculate the amount of drug remaining in the bloodstream after 12 hours

A_{12}=10e^{-0.0173\times12}

A_{12}=10e^{-0.2076}

                = 10×0.81253

                = 8.1 milligrams

b. In this part we have to calculate the time when A(t) = 5 milligrams

5=10e^{-0.0173\timest}

\frac{5}{10}=e^{-0.0173t}

0.5 = e^{-0.0173t}

Now we take natural log on both the sides of the equation.

ln(0.5) = ln(e^{-0.0173t})

-0.69314 = -0.0173t

t = \frac{0.69314}{0.0173}

t = 40.0658

 ≈ 40.07 hours

c. In this part we have to calculate the rate, by which amount of drug will decay in the bloodstream after 7 hours.

A_{7}=10e^{-0.0173\times7}

A_{7}=10e^{-0.1211}

              = 10×0.8859

              = 8.859 milligrams

6 0
3 years ago
Can someone help me with this slide pleaseeeee?? ASAP
diamong [38]
A dependent variable is a value that depends on another, so what relies on the other! :)
8 0
3 years ago
Nombre de las celulas oclusivas de la planta​
sertanlavr [38]

Answer:

Stoma

Explanation:

5 0
3 years ago
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