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2 years ago

On earth, a kilogram is equivalent to 2.2 pounds. [True] or [False]

Mathematics

2 answers:

aleksley [76]2 years ago

5 0

Answer:

false

Step-by-step explanation:

because I say

Bond [772]2 years ago

3 0

False one pound is equal to less than one kilo

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14 : ( 8 - 1 ) + 6 + 7 : 7 - ( 12 - 10 ) : 2 =

goldfiish [28.3K]

The correct answer is 14.

7 0

2 years ago

In a right triangle, one leg is 20 cm and the hypotenuse is 30 cm. To the nearest hundredth of a cm, find the length of the miss

max2010maxim [7]

Answer:

Step-by-step explanation:

Use Pythagoras’ theorem

square of hypotenuse = sum of squares of two other sides

let the missing side be d

30^2 = 20^2 + d^2

600 = 400 + d^2

d^2 = 200

d = square root of 200

d = 14.142 cm

3 0

2 years ago

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Can you PLEASE help with problem 4. (IF YOU KNOW IT)

Andru [333]

The total was $29.
1. Write an equation. 24+(2.50*2)= x
2. Solve your equation using PEMDAS
*2.5*2=5
*5+24=
3. Simplify equation.
5+24=29

4 0

2 years ago

If f(x) = 3x2 - x, find f(-2).<br><br> 10<br> 14<br> 38

mojhsa [17]

f(x) = 3x^2-x

F(-2)

replace x with -2

3(-2)^2 - -2 =

3*4 +2 = 14

Answer is 14

6 0

2 years ago

Read 2 more answers

A strobe light is located at the center of a square dance room. the rotating light is 40 feet from each of the square walls and

Effectus [21]

The equation of the rotating light is an illustration of a secant function

The equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

<h3>How to determine the equation</h3>

The equation is a secant function represented by

$y =A\sec(Bt)$

Where:

A represents the amplitude

So, we have:

$A = 40$ --- the distance of the light from each square wall

B represents the period, and it is calculated as:

$B = \frac{2\pi}{T}$

The light completes its full rotation every 6 seconds.

This means that,

T = 6

So, we have:

$B = \frac{2\pi}{6}$

Simplify

$B = \frac{\pi}{3}$

Substitute values for A and B in $y =A\sec(Bt)$

$y = 40\sec(\frac{\pi}{3}t)$

Rewrite as a function

$d(t) = 40\sec(\frac{\pi}{3}t)$

Hence, the equation that represents the distance between the center of the circle and the light source is $d(t) = 40\sec(\frac{\pi}{3}t)$

Read more about trigonometry functions at:

brainly.com/question/1143565

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2 years ago