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3 years ago

What is the solution of sqrt2x+4=15

Mathematics

2 answers:

melomori [17]3 years ago

7 0

Answer:

x = 126

Step-by-step explanation:

Square both sides of the equation. (sqrt2x+4)^2 = 16^2

2x+4 = 256

Then you should solve for x. (First Subtract 4 from both sides; Then simplify; Next divide both sides by 2; Finally, simplify once more)

This should give you your answer. (x = 126)

Hope this helps! ^-^

Kitty [74]3 years ago

7 0

Answer:

x = 72

Step-by-step explanation:

sqrt {2x} +4 = 16

sqrt {2x} = 12

2x = 12 ^ 2

x = 144/2

x = 72

If you wanted to write:

sqrt {2x + 4} = 16

2x + 4 = 16 ^ 2

2x + 4 = 256

2x = 252

x = 252/2

x = 126

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Answer:

BAF and FAD

Step-by-step explanation:

In order for an angle to have A.F as a side, it must have the letters A.F or FA in its name.

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In EAF, the angle is made of rays AE and A.F. In CAE, the angle is made up of rays AC and AE. This is not the correct pair.

In BAF, the angle is made of rays AB and A.F. In EAD, the angle is made up of rays AE and AD. This is not the correct pair.

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2 years ago

Select the two values of x that are roots of this equation 3x^2 + 1 =5x

Zina [86]

Answer:

x = 1.434 and x=0.232

Step-by-step explanation:

To find the root of the equation stated above we need to:

(1) Write the polynomial equation with zero on the right hand side:

$3x^{2} + 1 = 5x$ ⇒ $3x^{2} -5x + 1 = 0$

(2) Divide the whole equation by 3

$3x^{2} -5x + 1 = 0$ ⇒ $x^{2} -\frac{5}{3}x + \frac{1}{3}= 0$

(3) Use the quadratic formula to solve the quadratic equation:

The quadratic formula states that the two solutions for a quadratic equation is given by:

$\frac{-b±\sqrt{b^{2} - 4ac}}{2a}$ (1)

In this case, a = 1, b = $-\frac{5}{3}, c= \frac{1}{3}$

Substituiting a, b and c in equation (1) We get:

$\frac{-\frac{5}{3}±\sqrt{(-\frac{5}{3})^{2} - 4(1)(\frac{1}{3})}}{2(1)}$ (1)

The two solutions are:

x = 1.434 and x=0.232

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2 years ago