A thermal insulated sleeve is used to cover the lateral surface of a hot water heater to help improve efficiency. The hot water
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There are 6! possible permutations of the blue books, 2 possible permutations of the red books, 4! possible permutations of the green books and 3! possible permutations of the three color groups. therefore the total number of ways of arranging the books is given by:
We know that
the equation of a vertical parabola in vertex form
y=a*(x-h)²+k
(h,k)------> (0,5)
y=a*(x-0)²+5
y=a*x²+5
substitute the point (2,9) in the equation
9=a*(2)²+5------> 9=4*a+5-------> 4*a=9-5-----> 4*a=4-----> a=1
the equation of the vertical parabola is
y=x²+5
the equation of a horizontal parabola in vertex form
x=a*(y-k)²+h
(h,k)------> (0,5)
x=a*(y-5)²+0
x=a*(y-5)²
substitute the point (2,9) in the equation
2=a*(9-5)²------> 2=16*a------> a=1/8
the equation of the horizontal parabola is
x=(1/8)*(y-5)²
the answer is
the equation of the vertical parabola is y=x²+5
the equation of the horizontal parabola is x=(1/8)*(y-5)²
see the attached figure
the equation of a vertical parabola in vertex form
y=a*(x-h)²+k
(h,k)------> (0,5)
y=a*(x-0)²+5
y=a*x²+5
substitute the point (2,9) in the equation
9=a*(2)²+5------> 9=4*a+5-------> 4*a=9-5-----> 4*a=4-----> a=1
the equation of the vertical parabola is
y=x²+5
the equation of a horizontal parabola in vertex form
x=a*(y-k)²+h
(h,k)------> (0,5)
x=a*(y-5)²+0
x=a*(y-5)²
substitute the point (2,9) in the equation
2=a*(9-5)²------> 2=16*a------> a=1/8
the equation of the horizontal parabola is
x=(1/8)*(y-5)²
the answer is
the equation of the vertical parabola is y=x²+5
the equation of the horizontal parabola is x=(1/8)*(y-5)²
see the attached figure
Answer:
Mike is not right
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared
Let
z----> the scale factor
x----> surface area of the enlarged rectangular prism
y-----> surface area of the original rectangular prism
so
In this problem we have
substitute
so
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism
therefore
Mike is not right
<em>Verify with an example</em>
we have a rectangular prism
The surface area of the prism is equal to
substitute the values
If he doubles each dimension of any rectangular prism
then
the new dimensions will be
The new surface area will be
therefore
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism