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tangare [24]
2 years ago
6

2. You are creating a cone-shaped hat for a kid’s costume. You measure the circumference of the child’s head and find it to be 2

0.5 inches.
A. Determine the radius of the hat.

B. You want the hat to have a slant height of 8 inches. Draw an image that models this situation and include all of the measurements you know.

C. How much material would you need to make the hat? Your answer should be in square inches.


3. For this question, we will find the surface area of a cylinder, using an object from your kitchen.

A. Locate a canned good from your kitchen. Some examples include a can of soup, a can of vegetables, or a can of fruit. Describe the type of can that you are using.

B. Draw a picture of your canned good. Measure the height of the can and the diameter of the top surface. Label the measurements on your picture.

C. Calculate the surface area of the canned good. Show all of your work. Round your answer to the nearest whole number.
Mathematics
1 answer:
Monica [59]2 years ago
3 0
Just draw a triangle(front view) and the slant/inclined sides of it are known to be 8 and you found out radius as 3.26. so mark the diameter by doubling radius.

so the material required would be a slice(like pizza slice) of a circle of radius= 8 and arc length = circumference given ,that is 20.5

now using this find the area of sector/slice. its the answer to the last bit.

now coming to next question, go to the kitchen and take any can and measure its dia and height by using a scale. and you might already know the formula to find the suface area of cylinder.
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ELEN [110]

Question:

Find the point (,) on the curve y = \sqrt x that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

Step-by-step explanation:

y = \sqrt x can be represented as: (x,y)

Substitute \sqrt x for y

(x,y) = (x,\sqrt x)

So, next:

Calculate the distance between (x,\sqrt x) and (3,0)

Distance is calculated as:

d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}

So:

d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}

d = \sqrt{(x-3)^2 + (\sqrt x)^2}

Evaluate all exponents

d = \sqrt{x^2 - 6x +9 + x}

Rewrite as:

d = \sqrt{x^2 + x- 6x +9 }

d = \sqrt{x^2 - 5x +9 }

Differentiate using chain rule:

Let

u = x^2 - 5x +9

\frac{du}{dx} = 2x - 5

So:

d = \sqrt u

d = u^\frac{1}{2}

\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}

Chain Rule:

d' = \frac{du}{dx} * \frac{dd}{du}

d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}

d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}

d' = \frac{2x - 5}{2\sqrt u}

Substitute: u = x^2 - 5x +9

d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}

Next, is to minimize (by equating d' to 0)

\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0

Cross Multiply

2x - 5 = 0

Solve for x

2x  =5

x = \frac{5}{2}

Substitute x = \frac{5}{2} in y = \sqrt x

y = \sqrt{\frac{5}{2}}

Split

y = \frac{\sqrt 5}{\sqrt 2}

Rationalize

y = \frac{\sqrt 5}{\sqrt 2} *  \frac{\sqrt 2}{\sqrt 2}

y = \frac{\sqrt {10}}{\sqrt 4}

y = \frac{\sqrt {10}}{2}

Hence:

(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})

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vekshin1

Chris and Jim must replace a <em>total</em> quantity of 17 tyres.

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In this problem we must use an inequality of the form f(x) ≥ a, where f(x) is the difference between the number of tyres replaced by Jim and the number of tyres replaced by Chris:

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Answer: 20 Decibels

Step-by-step explanation:

I don't know

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